Answer: the bridge is 11.025 m high
Step-by-step explanation:
Given that;
Time taken to hit the water t = 1.5 sec
height of bridge = ?
lets take a look at the equation of motion;
y(t) = y₀ + (1/2)at²
with initial velocity zero and we know that acceleration due to gravidity is 9.8m/s
we substitute
y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²
y(t) = (1/2)gt² = (1/2) × 9.8 × (1.5)²
y(1.5) = 11.025 m
Therefore, the bridge is 11.025 m high
4x - 2y = 14
y = 0.5x -1
Get just one variable on one side for both equations.
4x - 2y = 14 ⇒ 4x = 2y + 14 ⇒ 4x - 14 = 2y
y = 0.5x - 1 ⇒ x - 2 = 2y
Use the transitive property and then solve for x.
x-2 = 4x-14
12 = 3x
x = 4
<em>Edit: Apprently I didn't use substitution. Oops! Sorry...</em>
The scale factor is 1/3.
To find this scale factor, choose a set of sides to compare lengths. For example, taking the left sides of the triangles, which is 9 and 3. 9 is 3 times bigger than the triangle on the right, so that gives us the scale factor of 1/3.
