All categories

1 year ago

Hi please help me answer this!!

Mathematics

1 answer:

just olya [345]1 year ago

7 0

The numbers that are irrational are B. √72 and D.√23.

<h3>What are irrational numbers?</h3>

Irrational numbers are those that have infinite numbers after the decimal. These numbers are also none repeating.

When the above are solved:

√25 = 5

√144 = 12

√23 = 4.79583152331...

√72 = 8.48528137424...

The only two numbers with non-repeating and infinite numbers are √72 and √23.

Find out more on irrational numbers at brainly.com/question/20400557

#SPJ1

You might be interested in

I have 345 students and I need to fit them all into chairs. However, there are some requirements my seating plan has to keep to:

sveta [45]

In each row, the 15 number of the student is arranged. For the given condition, the equal number of the student is to be arranged.

<h3>What is seating arrangement?</h3>

A seating arrangement is an arrangement shows that how the peoples are arranged so that the complete utilization is done.

The given data in the problem is;

The total no of student is 345 students

If the same number of the students are to be arranged for the given row, the following calculation is done;

The numbers of the student in each row is found as;

$\rm n= \frac{Total \ no \ of \ student\ }{Total\ no \of \ rows } \\\\\ n= \frac{345}{23} \\\\ n= 15 \ student$

Hence, in each row, the 15 no of the student is arranged.

To learn more about the seating arrangement, refer to the link;

brainly.com/question/13492666

#SPJ1

3 0

2 years ago

Let a=(1,2,3,4), b=(4,3,2,1) and c=(1,1,1,1) be vectors in R4. Part (a) [4 points]: Find (a⋅2c)b+||−3c||a. Part (b) [6 points]:

love history [14]

Solution :

Given :

a = (1, 2, 3, 4) , b = ( 4, 3, 2, 1), c = (1, 1, 1, 1) ∈ $R^4$

a). (a.2c)b + ||-3c||a

Now,

(a.2c) = (1, 2, 3, 4). 2 (1, 1, 1, 1)

= (2 + 4 + 6 + 6)

= 20

-3c = -3 (1, 1, 1, 1)

= (-3, -3, -3, -3)

||-3c|| = $\sqrt{(-3)^2 + (-3)^2 + (-3)^2 + (-3)^2 }$

$=\sqrt{9+9+9+9}$

$=\sqrt{36}$

= 6

Therefore,

(a.2c)b + ||-3c||a = (20)(4, 3, 2, 1) + 6(1, 2, 3, 4)

= (80, 60, 40, 20) + (6, 12, 18, 24)

= (86, 72, 58, 44)

b). two vectors $\vec A$ and $\vec B$ are parallel to each other if they are scalar multiple of each other.

i.e., $\vec A=r \vec B$ for the same scalar r.

Given $\vec p$ is parallel to $\vec a$ , for the same scalar r, we have

$\vec p = r (1,2,3,4)$

$\vec p = (r,2r,3r,4r)$ ......(1)

Let $\vec q = (q_1,q_2,q_3,q_4)$ ......(2)

Now given $\vec p$ and $\vec q$ are perpendicular vectors, that is dot product of $\vec p$ and $\vec q$ is zero.

$q_1r + 2q_2r + 3q_3r + 4q_4r = 0$

$q_1 + 2q_2 + 3q_3 + 4q_4 = 0$ .......(3)

Also given the sum of $\vec p$ and $\vec q$ is equal to $\vec b$ . So

$\vec p + \vec q = \vec b$

$(r,2r,3r,4r) + (q_1+q_2+q_3+q_4)=(4, 3,2,1)$

∴ $q_1 = 4-r , \ q_2=3-2r, \ q_3 = 2-3r, \ q_4=1-4r$ ....(4)

Putting the values of $q_1,q_2,q_3,q_4$ in (3),we get

$r=\frac{2}{3}$

So putting this value of r in (4), we get

$\vec p =\left( \frac{2}{3}, \frac{4}{3}, 2, \frac{8}{3} \right)$

$\vec q =\left( \frac{10}{3}, \frac{5}{3}, 0, \frac{-5}{3} \right)$

These two vectors are perpendicular and satisfies the given condition.

c). Given terminal point is $\vec a$ is (-1, 1, 2, -2)

We know that,

Position vector = terminal point - initial point

Initial point = terminal point - position point

= (-1, 1, 2, -2) - (1, 2, 3, 4)

= (-2, -1, -1, -6)

d). $\vec b = (4,3,2,1)$

Let us say a vector $\vec d = (d_1, d_2,d_3,d_4)$ is perpendicular to $\vec b.$

Then, $\vec b.\vec d = 0$

$4d_1+3d_2+2d_3+d_4=0$

$d_4=-4d_1-3d_2-2d_3$

There are infinitely many vectors which satisfies this condition.

Let us choose arbitrary $d_1=1, d_2=1, d_3=2$

Therefore, $d_4=-4(-1)-3(1)-2(2)$

= -3

The vector is (-1, 1, 2, -3) perpendicular to given $\vec b.$

6 0

3 years ago

The total cost to rent a row boat is $16 times the number of hours the boat is used. Write an equation to model this situation i

uysha [10]

C=16h
C, the total cost is equal to 16 dollars per hour, h

7 0

3 years ago

Anonymous 3 years ago

scZoUnD [109]

I'm in 7th grade and I need help with my math homework

8 0

3 years ago

What are the mean and the mode of the following sets of data 5 12 1 5 7

Alik [6]

To find the mean (average), u add up all ur numbers, then divide by how many numbers there are.
mean = (5 + 12 + 1 + 5 + 7) / 5 = 30/5 = 6

To find the mode (and there does not have to be one)...u find the number that is used the most. That number would be 5...because it is used twice, whereas, the other numbers are just used once.

6 0

3 years ago

Read 2 more answers