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2 years ago

8

Your friend borrows $7500 to buy an all-terrain vehicle (ATV). The simple annual interest rate is 6%. She pays off the loan afte

r 5 years of equal monthly payments. How much is each payment?

1 answer:

e-lub [12.9K]2 years ago

6 0

Answer:

$162.50

Explanation:

The total amount to be paid is 7500+5(7500)(0.06)=$9750.

There were a total of (5)(12)=60 payments, so each payment is 9750/60 = $162.50.

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What is the value of v in the equation -25=-(4v+7)+10

Wittaler [7]

Answer:

Therefore the value of v in the equation is 7

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3 years ago

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If line n bisects CE, find CD.

Artist 52 [7]

If it bisect, then using the Line Bisector Theorem, it must be equal.

So x+6=4x-21

get like terms on 1 side

x+6=4x-21

-x. +21

27= 3x

x=9

plug the x in

CD= 9+6

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3 years ago

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Write the fraction in terms 45/75

NARA [144]

The Answer is 3/5
<span>
The gcd of 45 and 75 is 15, so 45/75 = (15×3)/(15×5) = 15/15×3/5 = 3/5:

Answer: 3/5</span>

4 0

3 years ago

When we toss a coin, there are two possible outcomes: a head or a tail. Suppose that we toss a coin 100 times. Estimate the appr

marin [14]

Answer:

96.42% probability that the number of tails is between 40 and 60.

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

100 tosses, so $n = 100$

Two outcomes, both equally as likely. So $p = \frac{1}{2} = 0.5$

So

$E(X) = np = 100*0.5 = 50$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.5*0.5} = 5$

Estimate the approximate probability that the number of tails is between 40 and 60.

Using continuity correction.

$P(40 - 0.5 \leq X \leq 60 + 0.5) = P(39.5 \leq X \leq 60.5)$

This is the pvalue of Z when X = 60.5 subtracted by the pvalue of Z when X = 39.5. So

X = 60.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60.5 - 50}{5}$

$Z = 2.1$

$Z = 2.1$ has a pvalue of 0.9821

X = 39.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.5 - 50}{5}$

$Z = -2.1$

$Z = -2.1$ has a pvalue of 0.0179

0.9821 - 0.0179 = 0.9642

96.42% probability that the number of tails is between 40 and 60.

8 0

3 years ago

A track runner is eager to see if practicing helps her improve. She has plotted data on her weekly 100-meter dash times (s) as w

insens350 [35]

Answer:

$\displaystyle s = -\frac{1}{5}h + 20$

Step-by-step explanation:

<em>Time</em><em> </em>is the dependent variable, so you set your function equal to <em>s</em>. Then, the correlation of the graph has a $\displaystyle -\frac{1}{5}$ <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] from the y-intercept of $\displaystyle [0, 20],$ so we choose this answer choice.

I am joyous to assist you anytime.

4 0

3 years ago