A wombat can reach a top speed of 40km/hr. What is this speed in m/s?

Mathematics

1 answer:

Lena [83]1 year ago

5 0

Answer:

11,1 m/s

Step-by-step explanation:

40km/hr equals 11,1111111 m/s

11,1111111 simplified: 11,1

= 11,1 m/s

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Suppose we want to estimate the average weight of an adult male in Mexico. We draw a random sample of 2,000 men from a populatio

LenKa [72]

Answer:

1.- CI = 94% ( μ₀ - 1,04 < x < μ₀ + 1,04 )

2.- CI = 98 % ( μ₀ - 2,05 < x < μ₀ + 2,05 )

3.- CI = 96 % ( μ₀ - 1,75 < x < μ₀ + 1,75 )

Step-by-step explanation:

Sample size n = 3000000

Sample mean x = 200

Standard deviation s = 30

From z-table values of z(c):

CI 94 % Confidencial level α = 6 % α = 0,06 z(c) = 1,55

CI 98 % Confidencial level α = 2 % α = 0,02 z(c) = 2,05

CI 96 % Confidencial level α = 4 % α = 0,04 z(c) = 1,75

MOE = z(c) * σ/√n

1.-MOE = 1,55* 30 / √2000 MOE = 1,04

2.-MOE = 2,05*30/√2000 MOE = 1,38

3.-MOE = 1,75*30/√2000 MOE = 1,17

Then CI

1.- CI = 94 % ( μ₀ - MOE < x < μ₀ - MOE )

CI = ( μ₀ - 1,04 < x < μ₀ + 1,04 )

2.-CI = 98 %

CI = ( μ₀ - 2,05 < x < μ₀ + 2,05 )

3.- CI = 96 %

CI = ( μ₀ - 1,75 < x < μ₀ + 1,75 )

7 0

2 years ago

You toss a rock of mass m vertically upward. Air resistance can be neglected. The rock reaches a maximum height h above your han

laiz [17]

Answer:

$v=\sqrt{\frac{3gh}{2}}$

Step-by-step explanation:

If air resistance is neglected, the energy is constant. That means that in every point in the trajectory the energy is the same.

At the point of height h, all the energy is potential and velocity is zero (no kinetic energy)

$E=mgh$

At point of height h/4, some of the potential energy has transformed in kinetic energy and the velocity is no longer zero. But we know the total amount of energy is the same as the maximum height point.

With that information, we can calculate the velocity v:

$E=mg(\frac{h}{4})+m\frac{v^2}{2}=mgh\\\\m\frac{v^2}{2}=mg(h-\frac{h}{4})\\\\\frac{v^2}{2}=\frac{3gh}{4}\\\\v^2=\frac{3gh}{2}\\\\v=\sqrt{\frac{3gh}{2}}$