6×12 = 72
72 - (3x3) = 63
63 in ^2
A measurement that closely agrees with an accepted value is best described as a numerical
Double is double, so you can solve
.. 2 = 1*e^(.08t)
and get the correct value of t.
Taking logs,
.. ln(2) = .08t
.. ln(2)/.08 = t ≈ 8.7 . . . . years
V = u + at
u = 0
v = 0 + 1.5*5
v = 7.5 m/s
final velocity is 7.5 m/s
s = ut + 0.5at^2
s = 0 + (0.5*1.5*5^2)
s = (0.5*1.5*25)
s = 18.75 m
total travel distance is 18.75 m.
