Which protocol makes a connection, checks whether the data is received, and resends it if it is not?
1 answer:
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Answer:
Explanation:
The following code is written in Java. It creates a RomanNumberals class with all of the requested methods, including a convertNum method and displayResults method. The user is then asked to input a number within the main method. A RomanNumeral object is created, passed the userInput and all of it's methods are called for testing. A test output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter a number: ");
int number = in.nextInt();
RomanNumerals romanNumeral1 = new RomanNumerals();
romanNumeral1.setNumber(number);
System.out.println("Test getNumber Method: " + romanNumeral1.getNumber());
romanNumeral1.convertNumber();
romanNumeral1.displayResult();
}
}
class RomanNumerals {
int number;
String romanNumeral;
public RomanNumerals() {
}
public int getNumber() {
return number;
}
public void setNumber(int number) {
this.number = number;
}
public void convertNumber() {
switch (this.number) {
case 1: romanNumeral = "I"; break;
case 2: romanNumeral = "II"; break;
case 3: romanNumeral = "III"; break;
case 4: romanNumeral = "IV"; break;
case 5: romanNumeral = "V"; break;
case 6: romanNumeral = "VI"; break;
case 7: romanNumeral = "VII"; break;
case 8: romanNumeral = "VIII"; break;
case 9: romanNumeral = "IX"; break;
case 10: romanNumeral = "X"; break;
default: System.out.println("Not a valid number"); break;
}
}
public void displayResult() {
System.out.println("Number " + this.number + " is represented as " + this.romanNumeral);
}
}
