Question

5. calculate the percentage of water of crystallization in blue vitriol (copper sulphate pentahydrate), cuso4.5h2o

Answer 1

The percentage of water of crystallization in blue vitriol (copper sulphate pentahydrate), cuso4.5h2o is 36.07.

The molar weight of blue vitrol (cuso4.5h2o) is:

63.5 + 32+ 4(16) + 5(18) = 249.5 g/mol

The percentage of water of crystallization is :

                   = 5 × 18/249.5

                   = 0.3607 × 100

                   = 36.07%

 

The percentage of water of crystallization in blue vitriol (copper sulphate pentahydrate), cuso4.5h2o is 36.07.

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Answer 2

The percentage of water of crystallization in blue vitriol is 36.07%.

M(H₂O) = 2Ar(H) + Ar(O) x g/mol

M(H₂O) = 2 + 16 x g/mol

M(H₂O) = 18 g/mol; molar mass of water

M(CuSO₄·5H₂O) = Ar(Cu) + Ar(S) + 4Ar(O) + 5Mr(H₂O) x g/mol

M(CuSO₄·5H₂O) = 63.5 + 32 + 64 + 90 x g/mol

M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate

The percentage of water: 5M(H₂O) / M(CuSO₄·5H₂O) x 100%

The percentage of water: 90 g/mol / 249.5 g/mol x 100%

The percentage of water = 36.07%

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