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QveST [7]
3 years ago
8

Number the steps for balancing equations:

Chemistry
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

3,4,2,1

Explanation:

shtirl [24]3 years ago
6 0

Answer:

The correct answer will be 3,4,2,1

Explanation:

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Given the equation I = Q/t, solve for t.
larisa86 [58]

Answer: t=\frac{Q}{I}

Explanation:

I=\frac{Q}{t}

Multiply by t on both sides.

t*I=\frac{Q}{t}*t

tI=Q

Now divide by I to isolate t.

\frac{tI}{I}=\frac{Q}{I}

t=\frac{Q}{I}

5 0
3 years ago
If an object has more positive charges than negative charges, the object has an overall?
djyliett [7]
The object has an overall positive charge.
7 0
3 years ago
A gas cylinder contains 2.5 atm of ne, 0.8 atm of co2, and 3.4 atm of ar. what is the total pressure in the cylinder? g
Tatiana [17]
To answer this problem, we must make assumptions for simplicity. The first assumption is that, the system only consist of these 3 gases. The second assumption is that, these gases behave ideally. Thus, from Dalton's Law of Partial Pressure, the total pressure is simply the sum of their individual partial pressures.

Total pressure = 2.5 + 0.8 + 3.4 = <em>6.7 atm</em>
6 0
3 years ago
Can you make the particles of any of the substances stop moving?
ser-zykov [4K]

The particles cannot move around at all. The particles are, however, still in motion.

3 0
4 years ago
Calculate the molality of isoborneol in the product if, a) the melting point of pure camphor is 179°C and the melting point take
tresset_1 [31]

Answer:

The molality of isoborneol in camphor is 0.53 mol/kg.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = 165°C

Depression in freezing point = \Delta T_f=?

\Delta T_f=T- T_f=179^oC-165^oC=14^oC

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  organic compounds)

\Delta T_f=14^oC

14^oC=1\times 40^oC kg/mol\times m

m=\frac{14^oC}{1\times 40^oC kg/mol}=0.35 mol/kg

The molality of isoborneol in camphor is 0.53 mol/kg.

8 0
3 years ago
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