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densk [106]
2 years ago
9

How many CaH2 formula units are present in 8.294 g of CaH2?

Chemistry
1 answer:
raketka [301]2 years ago
7 0
RMM of CaH2=20+(1x2)=22
Number of moles or formula units
=mass/RMM
=8.294/22
=0.377
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If you increase the solute amount but keep the solution volume the same what
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What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?
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Answer: 0.8541 grams of HCl will be required.

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\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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\text{Number of moles}=\frac{0.610g}{78g/mol}

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Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

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Mass of HCl required will be = 0.8541 grams

3 0
3 years ago
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