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tia_tia [17]
1 year ago
10

Suppose you are performing a titration. at the beginning of the titration, you read the titrant volume as 2.42 ml. after running

the titration and reaching the endpoint, you read the titrant volume as 22.23 ml. what volume, in ml, of titrant was required for the titration?
Chemistry
1 answer:
Luda [366]1 year ago
5 0

The volume of titrant required for the titration would be 19.81 mL.

Since the burette was not filled to the zero mark during the titration and the level of base titrant was not filled to the 2.42 mL mark. As a result, the difference between the two values represents the total amount of titrant used in the titration.

therefore,

Volume of titrant after running titration - Volume of titrant before running titration  = total titrant required for the titration

22.23 - 2.42 = 19.81 mL

What Exactly Is Titration?

Titration is a laboratory technique that uses a solution with known volume and concentration to determine the concentration of an unknown solution. Between the two solutions, an oxidation-reduction reaction or acid-base neutralization occurs, and the known quantities are used to calculate the unknown. The known concentration standard solution is referred to as the titrant or titrator, while the unknown concentration solution is referred to as the titrand or analyte.

Find more on titration at : brainly.com/question/21881827

#SPJ4

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The density of the solid object will be 2.63 g/mL

<h3>What is density?</h3>

Density of objects = mass/volume.

Recall that an object will always displace its own volume when placed in a liquid.

Volume of the solid object = Cylinder reading after immersing the object in the water - cylinder reading before immersing the object in the water.

             = 48.1 - 20.4

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Mass of the solid object = 73.05 g

Density of the object = 73.05/27.8

                                         = 2.63 g/mL

More on density can be found here: brainly.com/question/15164682

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3 0
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A gas has a volume of 240 mL and a pressure of 0.99 atm. If the pressure is decreased to 0.951 atm, what is the new volume of th
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V2 = 250 ml

Explanation:

Given:

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