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tia_tia [17]
2 years ago
10

Suppose you are performing a titration. at the beginning of the titration, you read the titrant volume as 2.42 ml. after running

the titration and reaching the endpoint, you read the titrant volume as 22.23 ml. what volume, in ml, of titrant was required for the titration?
Chemistry
1 answer:
Luda [366]2 years ago
5 0

The volume of titrant required for the titration would be 19.81 mL.

Since the burette was not filled to the zero mark during the titration and the level of base titrant was not filled to the 2.42 mL mark. As a result, the difference between the two values represents the total amount of titrant used in the titration.

therefore,

Volume of titrant after running titration - Volume of titrant before running titration  = total titrant required for the titration

22.23 - 2.42 = 19.81 mL

What Exactly Is Titration?

Titration is a laboratory technique that uses a solution with known volume and concentration to determine the concentration of an unknown solution. Between the two solutions, an oxidation-reduction reaction or acid-base neutralization occurs, and the known quantities are used to calculate the unknown. The known concentration standard solution is referred to as the titrant or titrator, while the unknown concentration solution is referred to as the titrand or analyte.

Find more on titration at : brainly.com/question/21881827

#SPJ4

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HELPPP PLEASE!!!!!!!!!!!!!
Naddik [55]

Answer:

<h2>The ans is bery simple it is point a </h2>
3 0
3 years ago
Which of the following is the correct set-up for the problem: How many grams of water will be produced from 3.2 moles of oxygen
suter [353]

Option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

<h3>Reaction between oxygen and ethene</h3>

Ethene (C2H4) burns in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O) along with the evolution of heat and light.

C₂H₄  + 3O₂   ----- > 2CO₂ + 2H₂O

from the equation above;

3 moles of O₂ ---------> 2(18 g) of water

3.5 moles of O₂ ----------> x

x = 3.2 \times [\frac{2 \ moles \ H_2O}{3 \ moles \ O_2}  ] \times[ \frac{18.02 \ g \ H_2O}{1 \ mole \ H_2O} ]

Thus, option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.

Learn more about reaction of ethene here: brainly.com/question/4282233

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6 0
2 years ago
0.0625 mol of an ideal gas is contained within a 1.0000 Lvolume container. Its pressure is 142,868 Pa and temperature is X K . W
aliya0001 [1]

<u>Answer:</u> The temperature of the ideal gas is 2.75\times 10^2K

<u>Explanation:</u>

To calculate the temperature, we use the equation given by ideal gas equation:

PV=nRT

where,

P = Pressure of the gas = 142,868 Pa = 142.868 kPa    (Conversion factor: 1 kPa = 1000 Pa)  

V = Volume of gas = 1.0000 L

n = number of moles of ideal gas = 0.0625 moles

R = Gas constant = 8.31\text{L kPa }mol^{-1}K^{-1}

T = temperature of the gas = ?

Putting values in above equation, we get:

142.868kPa\times 1.0000=0.0625mol\times 8.31\text{L kPa }mol^{-1}K^{-1}\times T\\\\T=275K=2.75\times 10^2K

Hence, the temperature of the ideal gas is 2.75\times 10^2K

8 0
4 years ago
If a mixture of gases contained 78% nitrogen at a pressure of and 22% carbon dioxide at , what is the total pressure of the syst
Naddika [18.5K]
The pressures given are the partical pressures of the two gases.

The law of Dalton or of the partial pressures states that the total pressure of a mixture of gases is equal to the sum of the pressures of all the gases.

So, in this case:

Total pressure = pressure of nitrogen + pressure of carbon dioxyde.

Of course both terms must be in the same units.

i have found that the pressures for this problem are:

Pressure of nitrogen = 984 torr

Pressure of carbon dioxyde = 345 torr

Total pressure = 984 torr + 345 torr = 1329 torr.

Now convert to atm: 1 atm = 760 torr

=> 1329 torr * 1 atm / 760 torr = 1.74868 atm ≈ 1.75 atm

Answer: 1.75 atm

4 0
4 years ago
What is silicone used for
enot [183]

Answer:

sealants, adhesives, lubricants, medicine, cooking utensils, and thermal and electrical insulation

Explanation:

6 0
3 years ago
Read 2 more answers
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