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LUCKY_DIMON [66]
3 years ago
6

Did democritus belive atoms retain there identity as a chemical reaction

Chemistry
2 answers:
mihalych1998 [28]3 years ago
4 0
No He believed tiny particles were invisible and couldn't be changed....So No The person that believed in this was Dalton .
tresset_1 [31]3 years ago
4 0
Hey there!

Democritus did NOT believe this. The person that believed in this, was DALTON.

Your answer is: No, Democritus did not believe in this.
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miss Akunina [59]

Answer:

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Explanation:

Because it decreases from October trough december

5 0
3 years ago
A car with a mass of 1,000 kg is moving at a speed of 20 m/s. What is the car's kinetic energy?
shtirl [24]

The answer would be 200000 J. the equation for kinetic energy is 1/2 mass times velocity squared. 1/2 of 1,000 is 500. and 20*20 is 400. So, multiply 400 by 500, and that gives you your answer,

7 0
2 years ago
What is a level 7-8 grade science fair project I can do?
Delicious77 [7]
Making an atom or a virus structure
4 0
3 years ago
A human red blood cell is about 0.000008 meters in diameter which of the following represents this number in scientific notation
lukranit [14]

<u>Given:</u>

Diameter of a red blood cell = 0.000008

<u>To determine:</u>

The scientific notation corresponding to the given number

<u>Explanation:</u>

Scientific notation is a concise way of representing a very large or small number. It is written in two parts:

Given Number = Digits * Power of 10

In this case we have:

0.000008 = 8.0 * 10⁻⁶

3 0
3 years ago
Which statement is correct regarding the reaction below? 3A + 2B yields C + 2D The rate of formation of D is twice the rate of d
Vedmedyk [2.9K]

Answer:

The correct statements are:

The rate of disappearance of B is twice the rate of appearance of C.

Explanation:

Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.

3A + 2B → C + 2D

Rate of the reaction:

R=-\frac{1}{3}\times \frac{d[A]}{dt}=-\frac{1}{2}\times \frac{d[B]}{dt}

-\frac{1}{3}\times \frac{d[A]}{dt}=\frac{1}{1}\times \frac{d[C]}{dt}

-\frac{1}{3}\times \frac{d[A]}{dt}=\frac{1}{2}\times \frac{d[D]}{dt}

The rate of disappearance of B is twice the rate of appearance of C.

\frac{1}{1}\times \frac{d[C]}{dt}=-\frac{1}{2}\times \frac{d[B]}{dt}

2\times \frac{1}{1}\times \frac{d[C]}{dt}=-\frac{1}{1}\times \frac{d[B]}{dt}

8 0
3 years ago
Read 2 more answers
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