The problem above can be solved using M1V1=M2V2 where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,
(3.0 M)(V2)=(250 mL)(1.2M)
V2 (3.0)= 300
V2= 100 mL
Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.
Answer:
0.375 grams are needed to make 25 mL solution.
Explanation:
Mass of
cuprous nitrate required to make 1 l of solution = 15 g.
1 L = 1000 mL
Mass of
cuprous nitrate required to make 1000 mL of solution = 15 g
Mass of
cuprous nitrate required to make 1 mL of solution:

Mass of
cuprous nitrate required to make 25 mL of solution:

0.375 grams are needed to make 25 mL solution.
Answer:
Answer B) 4.2x10^17
Explanation:
To produce the reaction 3 using reaction 1 and 2 we need to invert the order of the first reaction the second in the same order, as it's shown:


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Due to the inversion of the first equation, the equilibrium constant of the new reaction is K1'=1/K1.=2.4x10^30
Finally, the new equilibrium constant K3 is the product of the previous constants:
K3=K1'*K2=4.2x10^17
The hydrosphere contains all the water
Combination: Joining of two different substances to form a more complex substance.
Decomposition: Breaking of a compound into two or more products.
I HOPE THIS HELPS! :3