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AfilCa [17]
1 year ago
15

On a hot summer day, the temperature of air in Arizona reaches 108°F. What is the speed of sound in air at this temperature? (Th

e speed of sound at 0°C is 331 m/s. Use the conversion 0°C = 273 K as necessary.)
______m/s
Physics
1 answer:
Hatshy [7]1 year ago
3 0

355.7 meter/ sec is the speed of sound in air at 108°F temperature because with the increase in temperature the speed of sound increases.

<h3>What is the relationship between speed of sound and temperature?</h3>

The speed of sound is directly proportional to the temperature. We know that directly proportional means when the temperature increases, the speed of sound also increases while on the other hand, when the temperature decreases, the speed of sound also decreases which shows direct relationship. That's why the speed of sound is 355.7 meter/ sec in air at 108°F temperature.

So we can conclude that 355.7 meter/ sec is the speed of sound in air at 108°F temperature because with the increase in temperature the speed of sound increase.

Learn more about speed here: brainly.com/question/13943409

#SPJ1

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Answer:

The force will increase in proportion to the mass of the objects

Explanation:

The acceleration due to gravity is always the same. It is expressed in meters per second squared or m/s². The figure of 9.81 m/s² is an average value that was taken after calculating the acceleration under different surfaces. In fact, the acceleration differs depending on the shape of the part of the earth in relation to the earth's magnetic field and force.

Thus, if one washer was 20 kg, the acceleration being 9.81 m/s² the weight will be:

F = ma

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If there are there washers, the weight will be:

F = 3 * 20 * 9.81

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The heat flows into the sample in the segment <u>    BC    </u>    will yield the value of the heat of fusion of this substance.

<h3>Heat of fusion:</h3>

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Answer:

E = \frac{8.99 x10^{9} \frac{Nm^2}{C^2} * 2x10^{-9} C}{(0.64m)^2} =43.85N

Explanation:

For this case we assume that we want to find the electrical field at the point P as we can see on the figure attached.

The electrical field wormula is given by:

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Where r is the distance from the point and the charge. On this case we can use the Pythagoras theorem and we got:

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