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agasfer [191]
3 years ago
8

HELP, 15 Points! How does uniform motion relate to velocity and acceleration?

Physics
1 answer:
Hatshy [7]3 years ago
3 0

Answer:

according to newton's first lawof motion an object with no net forceacting on its remains at rest if it is initiallity at rest and moves with a constant velocity if it is essential in motion ........if the force and mass are both constant then the objects moves with constant acceleration ..........hope this helps u dear .. ♥

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All atoms of the element potassium have 19 protons. One of the most stable types of potassium atoms has the mass number 39. How
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The formular for determinatio of mass number is this:
Mass number = number of proton + number of neutron
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Mass number = 39
Proton number = 19
Number of proton = ?
Number of neutron = mass number -  number of proton
Number of neutron= 39 - 19 = 20
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Which value is equivalent to 7.2 kilograms?
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Lions can run at speeds up to approximately 80.0 km / h. A hungry 109 kg lion running northward at top speed attacks and holds o
sukhopar [10]

Answer:

17.34 m/s

Explanation:

Given:

Mass of lion (m₁) = 109 kg

Initial speed of lion (v₁) = 80.0 km/h (Northward direction)

Mass of gazelle (m₂) = 39.0 kg

Initial speed of gazelle (v₂) = 78.5 km/h (Eastward direction)

Final velocity of both lion and gazelle is, v_f=?

First, let us convert the speeds from km/h to m/s using the conversion factor.

We know that, 1 km/h = 5/18 m/s

Therefore,

v_1= 80.0\ km/h=80\times \frac{5}{18}=22.22\ m/s\\\\v_2=78.5\ km/h=78.5\times \frac{5}{18}=21.81\ m/s

Now, the concept of conservation of total momentum is used here as this is a case of perfectly inelastic collision. In inelastic collision, the masses move together with same velocity after collision.

Here, as the lion and gazelle are moving in directions at right angles to each other, the vector sum of their momentums will give the net initial momentum of the system.

So, initial momentum is given as:

P_i=\sqrt{P_1^2+P_2^2}\\\\Where,\\\\P_1\to initial\ momentum\ of\ lion\\P_2\to initial\ momentum\ of\ gazelle

Now, we calculate P₁ and P₂.

P_1=m_1v_1=(109\ kg)(22.22\ m/s) = 2421.98\ Ns\\\\P_2=m_2v_2=(39\ kg)(21.81\ m/s) = 850.59\ Ns

Therefore, the net initial momentum of the system is given as:

P_i=\sqrt{(2421.98)^2+(850.59)^2}=2567\ Ns

The final momentum of the system is given as:

P_f=(m_1+m_2)(v_f)\\\\P_f=(109+39)v_f\\\\P_f=148v_f

From the law of conservation of momentum, the final momentum is equal to the initial momentum. So,

P_f=P_i\\\\148v_f=2567\\\\v_f=\frac{2567}{148}=17.34\ m/s

Therefore, the final speed of the lion-gazelle system is 17.34 m/s

3 0
3 years ago
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