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Contact [7]
3 years ago
10

All spiders are very sensitive to vibrations. An orb spider sits at the center of its web and monitors radial threads for vibrat

ions created when an insect lands. Assume that these threads are made of silk with a linear density of 1.0 x 10-5 kg/m under a tension of 0.40 N. If an insect lands in the web 30 cm from the spider, how long will it take for the spider to find out
Physics
1 answer:
Roman55 [17]3 years ago
3 0

Answer:

The time taken by spider to catch insect 1.5 ms

Explanation:

Given:

Linear mass density \mu = 1 \times 10^{-5} \frac{kg}{m}

Tension on the string T = 0.40 N

Distance between web and insect lands x = 30 \times 10^{-2} m

From the formula of velocity in string,

   v = \sqrt{\frac{T}{\mu} }

First find the velocity and then find time,

   v = \sqrt{\frac{0.40}{1 \times 10^{-5} } }

   v = 200 \frac{m}{s}

The time taken is given by,

   v = \frac{x}{t}

   t = \frac{x}{v}

   t = \frac{30 \times 10^{-2} }{200}

   t = 1.5 \times 10^{-3} sec

   t = 1.5 ms

Therefore, the time taken by spider to catch insect 1.5 ms

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For a person with a Near Point (NP) = 45 cm, what would be his prescription's lens power = _________ diopters A) 1.08 diopters
natita [175]

Answer:

The power of lens is 2.22 D.

Explanation:

Given that,

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Using formula of lens

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3 years ago
The height of a transverse wave from the midpoint to the crest or trough is the .
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Explanation:

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3 years ago
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A 20.0-kg rock is sliding on a rough, horizontal surface at 8.00 m/s and eventually stops due to friction. The coefficient of ki
Neporo4naja [7]

Answer:

a = -1.961\,\frac{m}{s^{2}}, s = 16.318\,m, t = 4.079\,s

Explanation:

The equations of equilibrium for the rock are:

\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a

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After some algebraic handling, the following expression is found:

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a = - (0.2)\cdot (9.807\,\frac{m}{s^{2}} )

a = -1.961\,\frac{m}{s^{2}}

The distance travelled by the rock before stopping is:

s = \frac{(0\,\frac{m}{s} )^{2}-(8\,\frac{m}{s} )^{2}}{2\cdot (-1.961\,\frac{m}{s^{2}} )}

s = 16.318\,m

And the time is:

t = \frac{0\,\frac{m}{s}-8\,\frac{m}{s}}{(-1.961\,\frac{m}{s^{2}} )}

t = 4.079\,s

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3 years ago
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