1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Darina [25.2K]
3 years ago
13

1. Which has more kinetic energy, a 40 kg cheetah running at 25 m/s or a 4,000 kg elephant moving at 2 m/s? How much more energy

does it have?
2. At what speed would the animal with less KE have to travel to have the same kinetic energy as the animal with more KE?

3. Discuss the kinetic and potential energy of the ball on the end of a pendulum as it swings from point A to point B. Explain the kinetic energy and potential energy of the ball at each point and what happens to energy as the ball moves from point A to point B. In your discussion, answer the following questions: When is the kinetic energy of the ball zero and when is it at its highest? When is its potential energy at its lowest and at its highest? What happens to the kinetic energy and potential energy between point A and point B?
Physics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

1. The elephant has more kinetic energy at this speed and mass. It has 4,500 J more KE.

2. The elephant would have to go at a speed of 2.5 m/s to reach the same KE as the cheetah.

Explanation:

You would use the formula KE=1/2mv^2.

This formula would be filled in and completed twice, once for the elephant and once for the cheetah.

Cheetah:

KE = 1/2 (40) (25) ^2

KE = 12,500 J

Elephant:

KE = 1/2 (4,000) (2) ^2

KE = 8,000 J

This shows that the cheetah has more KE.

Then you would subtract the elephants amount of J from the cheetahs to find the difference.

Difference = 12,500 J - 8,000 J

Difference = 4,500 J

I hoped this helped with the first part :)

For the second part:

To find the speed the elephant would have to run you would fill in and complete the equation once more with different distance results.

KE = 1/2 (4,000) (2.5) ^2

KE= 12,500 J

You might be interested in
Is cold fusion science or pseudoscience
kondor19780726 [428]

The experiments that claimed to demonstrate cold fusion were found
to have been faulty by others who reviewed them.  Also, nobody else
was able to reproduce the finding in other laboratories.  In the world
of Science, this pretty much says that the initial claims were unfounded.

5 0
4 years ago
What is a structure that organizes motion of chromosomes
strojnjashka [21]
<span>Cytoplasm: <span>the entire contents of the cell, exclusive of the nucleus and bounded by the plasma membrane.

Hope this helped. :)</span></span>
4 0
3 years ago
Read 2 more answers
What are some examples of gravitational forces that keep an object in orbit? Pls give at least 2-3 example if you can.​
Lelu [443]

Answer:

Without any external forces a moving object will continue to move in a straight line. The gravitational force between the two objects will provide the centripetal force to keep the objects moving around one another.

1. satellite in orbit around the earth             (motion of earth is negligible)

2. moon in orbit around the earth     (center of motion several thousand miles        

                                                             from center of earth)

3. earth in orbit around sun    (center of rotation close to center of sun)

4. binary stars         (if masses of stars are equal center of rotation is in middle)

3 0
3 years ago
A 5.00X10^5 kg rocket is accelerating straight up. Its engines produce 1.250X10^7 N of thrust, and air resistance is 4.50X10^6 N
katrin [286]
<span>6.20 m/s^2 The rocket is being accelerated towards the earth by gravity which has a value of 9.8 m/s^2. Given the total mass of the rocket, the gravitational drag will be 9.8 m/s^2 * 5.00 x 10^5 kg = 4.9 x 10^6 kg m/s^2 = 4.9 x 10^6 N Add in the atmospheric drag and you get 4.90 x 10^6 N + 4.50 x 10^6 N = 9.4 x 10^6 N Now subtract that total drag from the thrust available. 1.250 x 10^7 - 9.4 x 10^6 = 12.50 x 10^6 - 9.4 x 10^6 = 3.10 x 10^6 N So we have an effective thrust of 3.10 x 10^6 N working against a mass of 5.00 x 10^5 kg. We also have N which is (kg m)/s^2 and kg. The unit we wish to end up with is m/s^2 so that indicates we need to divide the thrust by the mass. So 3.10 x 10^6 (kg m)/s^2 / 5.00 x 10^5 kg = 0.62 x 10^1 m/s^2 = 6.2 m/s^2 Since we have only 3 significant figures in our data, the answer is 6.20 m/s^2</span>
8 0
3 years ago
answer this question: When you can not see what is taking place, but other senses indicate occurrences. This is called _________
Phoenix [80]
This is called an indirect observation.
5 0
4 years ago
Other questions:
  • Solvents are the substances that dissolve solutes; therefore, solvents are always liquids.
    14·1 answer
  • What is the magnification of an astronomical telescope whose objective lens has a focal length of 71 cm and whose eyepiece has a
    8·1 answer
  • What's going to happen in 3 weeks ?
    6·2 answers
  • An elevator of massmis initially at rest onthe first floor of a building. It moves upward,and passes the second and third floors
    6·1 answer
  • What linear speed must an earth satellite have to be in a circular orbit at an altitude of 159 km?
    6·1 answer
  • The op amp in this circuit is ideal. R3 has a maximum value of 100 kΩ and σ is restricted to the range of 0.2 ≤ σ ≤ 1.0. a. Calc
    14·1 answer
  • What is the electric field at the point x=6.5 m? positive e-fields point to the right.?
    8·1 answer
  • Interactive Solution 28.5 illustrates one way to model this problem. A 7.11-kg object oscillates back and forth at the end of a
    13·1 answer
  • A 2.0   kg 2.0kg2, point, 0, start text, k, g, end text cart moving right at 5.0   m s 5.0 s m ​ 5, point, 0, start fraction, st
    13·2 answers
  • PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!