1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Darina [25.2K]
3 years ago
13

1. Which has more kinetic energy, a 40 kg cheetah running at 25 m/s or a 4,000 kg elephant moving at 2 m/s? How much more energy

does it have?
2. At what speed would the animal with less KE have to travel to have the same kinetic energy as the animal with more KE?

3. Discuss the kinetic and potential energy of the ball on the end of a pendulum as it swings from point A to point B. Explain the kinetic energy and potential energy of the ball at each point and what happens to energy as the ball moves from point A to point B. In your discussion, answer the following questions: When is the kinetic energy of the ball zero and when is it at its highest? When is its potential energy at its lowest and at its highest? What happens to the kinetic energy and potential energy between point A and point B?
Physics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

1. The elephant has more kinetic energy at this speed and mass. It has 4,500 J more KE.

2. The elephant would have to go at a speed of 2.5 m/s to reach the same KE as the cheetah.

Explanation:

You would use the formula KE=1/2mv^2.

This formula would be filled in and completed twice, once for the elephant and once for the cheetah.

Cheetah:

KE = 1/2 (40) (25) ^2

KE = 12,500 J

Elephant:

KE = 1/2 (4,000) (2) ^2

KE = 8,000 J

This shows that the cheetah has more KE.

Then you would subtract the elephants amount of J from the cheetahs to find the difference.

Difference = 12,500 J - 8,000 J

Difference = 4,500 J

I hoped this helped with the first part :)

For the second part:

To find the speed the elephant would have to run you would fill in and complete the equation once more with different distance results.

KE = 1/2 (4,000) (2.5) ^2

KE= 12,500 J

You might be interested in
a motorcycle traveling on the highway at a velocity of 120 kilometre-per-hour passes a car traveling at a velocity of 90 kilomet
musickatia [10]

Answer:

The relative velocity of the motorcycle to a passenger in the car is 30 km/h

Explanation:

The question relates to the principle of relative velocity and reference frames

The given parameters are;

The velocity of the motorcycle, v₁ = 120 km/h

The velocity of the car, v₂ = 90 km/h

The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as \underset{v}{\rightarrow}_{X|Y} = \underset{v}{\rightarrow}_{X} - \underset{v}{\rightarrow}_{Y}

Therefore, the relative velocity of the motorcycle to the car is v_{1|2} = v₁ -  v₂, which give;

v_{1|2}  = 120 km/h - 90 km/h = 30 km/h

The relative velocity of the motorcycle to a passenger in the car = 30 km/h.

5 0
3 years ago
How much of the electromagnetic spectrum is visible light?
Margarita [4]
I believe the answer is D, only a small part of it
8 0
3 years ago
Read 2 more answers
You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f
Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

u = 0m/s

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

s = ut+\frac{1}{2} at^2

Replacing,

1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2

u =6.4013m/s

The height of the acorn above the meter stick can be calculated as,

v^2 = u^2 +2gh

h = \frac{v^2-u^2}{2g}

h = \frac{6.4013^2-0^2}{2(9.8)}

h = 2.0906m

Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is

h = 2.0906+1.87

h = 3.9606m

4 0
4 years ago
A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerat
Readme [11.4K]

Answer:

The rocket above the ground is in 44 sec.

Explanation:

Given that,

Initial velocity = 92 m/s

Acceleration = 4 m/s²

Altitude = 1200 m

Suppose, How long was the rocket above the ground?

We need to calculate the time

Using equation of motion

s=ut-\dfrac{1}{2}at^2

Put the value into the formula

1200=92t+\dfrac{1}{2}\times4t^2

2t^2+92-1200=0

t=10\ sec

We need to calculate the velocity

Using equation of motion

v=u+at

Put the value into the formula

v=92+4\times10

v=132\ m/s

When the rocket hits the ground,

Then, h'=0

We need to calculate the time

Using equation of motion

h'=h+ut-\dfrac{1}{2}at^2

Put the value into the formula

0=1200+132t-\dfrac{1}{2}\times9.8t^2

4.9t^2-132t-1200=0

t=34\ sec

When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground

So, the total time will be

t'=34+10

t'=44\ sec

Hence, The rocket above the ground is in 44 sec.

7 0
4 years ago
A red horse and a black horse raced on a 1-mile long circular racetrack. The red horse
Lyrx [107]

Answer:

Explanation:

B- The red horse's average speed was greater than the black horse's average speed.

Red average speed = 1/120 = 0.00833 mi/s

Black average speed = 1/150 = 0.00667 mi/s

we only know about average speed based on the information given. Either horse could have had higher or lower, even negative,  instantaneous speed during some phase of the race.

5 0
3 years ago
Read 2 more answers
Other questions:
  • Is ecstasy dangerous to mix with alcohol? Explain.​
    7·1 answer
  • The speed at which an object is moving in a specific direction is its A speed. B acceleration rate. C velocity. D mechanical pot
    13·1 answer
  • A fully loaded, slow-moving freight elevator has a cab with a total mass of 1500 kg, which is required to travel upward 57 m in
    10·1 answer
  • If f(x) = 27+1, what is f\x) when x = 3?<br> 1
    13·1 answer
  • What are the bugs that make noises in the trees
    15·2 answers
  • As the pendulum swings from point A to Point E, what will happen to the values for potential and kinetic energy?
    12·1 answer
  • The charge within a small volume dv is dq=ρdv. the integral of ρdv over a cylinder of length l is the total charge q=λl within t
    8·2 answers
  • Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla
    10·1 answer
  • A pressure is applied to 20 l of water. the volume is observed to decrease to 18.7 l. calculate the applied pressure
    15·2 answers
  • A batter pops a ball straight up (a) If the ball returns to the height from which it was hit 4.5 s later, what was its
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!