Question

How long will it take for a falling object to reach 108 m/s if its initial velocity is 10 m/s?

Answer 1

Answer:

t=10 s

Step-by-step explanation:

v=u+gt

108=10+9.8t

108-10=9.8t

9.8t=98

$t=\frac{98}{9.8} =\frac{980}{98} =10$