Electron , photon and proton have wavelength which is option (a) , (b) and (c) .
- An electron is a solid negatively charged factor of an atom. Electrons exist outdoor of and surrounding the atom nucleus. Each electron includes one unit of bad charge (1.602 x 10^-19 coulomb)
- A proton is a subatomic particle discovered with inside the nucleus of each atom. The particle has a advantageous electric charge, identical and contrary to that of the electron
- A photon is a subatomic particle, having strength and momentum however no mass or electric powered charge, this is the quantum unit of electromagnetic radiation, together with light.
De Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.
De Broglie's relationship is given by
.....(1) where λ is known as de Broglie wavelength and m is mass , v is velocity , h = Plank’s constant .
With the help of equation (1) we can determine the wavelength of the electron and proton .
For photon , the wavelength is given by

Where h is plank's constant and c is speed of light , v is frequency of the inicident photons .
Thus, we can determine the wavelength of electron , photon and proton.
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