Answer:
Converted to heat energy
Explanation:
Some of the elastic potential energy is transformed into heat energy. When we stretch a rubber band, it is often observed that the rubber becomes warmer after the stretch and even during the stretch.
Some energy in the band initially at rest will be converted into elastic potential energy and heat energy as it is stretched .
- The heat energy is not usually accounted for since the major concern most times is the elastic energy.
- In this process, heat energy becomes a waste energy.
- By deducing the efficiency, we would find that this transformation is not efficient as predicted by one of the laws of thermodynamics.
From the diagram The value of cos C × sin A = 
<h3>Determine the numerical value of cos C × sin A</h3>
First step : determine the values of cos C and sin A
cos C = adjacent / hypotenuse
= a / b
= 
= √3/2
sin A = sin 60⁰
= √3/2
Therefore the numerical value of cos C * sin A =
In conclusion From the diagram The value of cos C × sin A =
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So if p=w/t
then 4400=(w)(200)
so you would multiply 4440•200 and get 880,000
Answer:
0.39 m/s²
Explanation:
From the question,
a = v²/r.................... Equation 1
Where v = velocity, r = radius.
Given: v = 222 mi/h = (222×0.44704) m/s = 9.83 m/s, r = 820 ft = (820×0.3048) m = 249.94 m.
Substitute thses values into equation 1
a = 9.83²/249.94
a = 96.63/249.94
a = 0.39 m/s²
Hence the acceleration is 0.39 m/s²
