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tankabanditka [31]
3 years ago
8

What is the purpose of a lanyard attached to an ignition safety switch??

Physics
2 answers:
raketka [301]3 years ago
6 0
So we want to know what is the purpose of a lanyard attached to a safety switch. So in case the operator falls overboard a safety switch is installed and connected to the operators hand or waist. Which ever is more practical. This safety switch turns off the motor. 
In-s [12.5K]3 years ago
6 0

Answer:

To turn the engine off in a situation of pilot of person overboard.

Explanation:

Various safety laws have been implemented to prevent damage due to boats in case the person driving the boat goes overboard i.e. falls off the boat. One of these mandates the use of lanyard type cutoff switch with the lanyard tied to the wrist or clothes of the person driving the boat. In case the person goes overboard the engine will be cutoff as the lanyard will pull along the cutoff switch as well.

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A force sets an object in motion when the force is multiplied by the time of its application.
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Please help me out id really appreciate it
Aliun [14]

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What is one way that continental rifts are similar to mid-ocean ridges and what is one that they are different?
adell [148]

Explanation:

Continental rifts and mid-ocean ridges are both features of a divergent plate margin.

In both cases plates are moving away from one another. Therefore they are creating new land masses.

  • A continental drift like the east African rift valley is where a continent begins to pull apart or diverges.
  • A mid-ocean ridge is divergent margin in the ocean.

They are different in that, continental rift occurs within the continental plate that are on land.

But:

 Mid-ocean ridges are in the oceanic crust in the ocean . They form the largest physiographic structure on the earth surface called the mid-ocean ridge.

learn more:

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3 0
3 years ago
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Fynjy0 [20]
C real,inverted and smaller than the object
6 0
3 years ago
510 g squirrel with a surface area of 935 cm2 falls from a 4.8-m tree to the ground. Estimate its terminal velocity. (Use the dr
Yuki888 [10]

Answer:

The terminal velocity is v_t  =17.5 \ m/s

Explanation:

From the question we are told that

       The mass of the squirrel is  m_s  =  50\ g  =  \frac{50}{1000} =  0.05 \  kg

      The surface area is   A_s =  935 cm^2  =  \frac{935}{10000} = 0.0935 \ m^2

       The height of fall is  h =4.8 m

        The length of the prism is l =  23.2 = 0.232 \ m

          The width of the prism is w =  11.6 =  0.116 \ m

 

The terminal velocity is mathematically represented as

       v_t  =  \sqrt{\frac{2 * m_s *  g }{\dho_s * C  * A } }

Where \rho  is the density of a rectangular prism with a constant values of \rho  =  1.21 \ kg/m^3

            C is the drag coefficient for a horizontal skydiver with a value = 1

            A  is the area of the prism the squirrel is assumed to be which is mathematically represented as

      A =  0.116 * 0.232

       A =  0.026912 \ m^2

 substituting values

      v_t  =  \sqrt{\frac{2 * 0.510 *  9.8 }{1.21 * 1  * 0.026912 } }

     v_t  =17.5 \ m/s

       

7 0
3 years ago
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