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2 years ago

What is the purpose of a lanyard attached to an ignition safety switch??

2 answers:

6 0

So we want to know what is the purpose of a lanyard attached to a safety switch. So in case the operator falls overboard a safety switch is installed and connected to the operators hand or waist. Which ever is more practical. This safety switch turns off the motor.

In-s [12.5K]2 years ago

6 0

Answer:

To turn the engine off in a situation of pilot of person overboard.

Explanation:

Various safety laws have been implemented to prevent damage due to boats in case the person driving the boat goes overboard i.e. falls off the boat. One of these mandates the use of lanyard type cutoff switch with the lanyard tied to the wrist or clothes of the person driving the boat. In case the person goes overboard the engine will be cutoff as the lanyard will pull along the cutoff switch as well.

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a constant force acts on an object of mass 10 kg for a duration of 2 seconds it increases the object velocity from 4metre per se

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Answer:

F=ma

a=v/t

a=vf-vi/t

a=8-4/2

a=4÷2

a=2msec*2

F=10×2

F=20N

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2 years ago

Your digestive system has three main functions digestion, absorption and elimination. in which organ does absorption begin?

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The Answer Is The Small Intestine

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2 years ago

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Use the general formulas for gravitational force and centripetal force to derive the relationship between speed (v) and orbital

german

Solution :

We know that :

Formula for Gravitational force is given by :

$F_g=\frac{Gmn}{r^2}$

where, G is the gravitational constant

M is the mass of the bigger body

m is the mass of the smaller body

r is the distance between the two bodies.

And the formula for the centripetal force is given by :

$F_c=\frac{mv^2}{r}$

where, m is the mass of the rotating body

v is the velocity

r is the radius of rotation of the body.

We know that mathematically, the gravitational force is equal to the centripetal force of the body.

Therefore,

$F_g=F_c$

$\frac{GMm}{r^2}=\frac{mv^2}{r}$

$\sqrt{\frac{GM}{r}}=v$

Hence derived.

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2 years ago

A cannon can make a maximum angle of 30 degrees with the horizon. What is the minimum speed of a cannon ball if it must clear a

stiks02 [169]

Answer:

28.3 m/s

Explanation:

From the question given above, the following data were obtained:

Angle of projection (θ) = 30°

Maximum height (H) = 10 m

Acceleration due to gravity (g) = 10 m/s²

Initial velocity (u) =?

Thus, we can obtain the minimum velocity cannon ball by using the following formula:

H = u²Sine² θ / 2g

10 = u² × (Sine 30)² / 2× 10

10 = u² × (0.5)² / 20

10 = u² × 0.25 / 20

10 = u² × 0.0125

Divide both side by 0.0125

u² = 10/ 0.0125

u² = 800

Take the square root of both side

u = √800

u = 28.3 m/s

Therefore, the minimum speed of the cannon ball is 28.3 m/s

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2 years ago

A runner can run a 400.0 meter lap in 50.0 seconds. He finishes at the same spot as he began. What is his average velocity?

cestrela7 [59]

8 meters per second. To find velocity is to divide distance by total time. so 400/50.

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3 years ago

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