Answer:
0.0000333 m³/s
Explanation:
using Bernoulli's equation
P1 + 1/2ρv1² + ρh1g = P2 + 1/2ρv2² + ρh2g
P1 = P2 both are atmospheric pressure; they cancel out
1/2ρv1² + ρh1g = 1/2ρv2² + ρh2g divide both side with ρ (rho)
1/2v1² + h1g = 1/2v2² +h2g
collect the like terms
h1g - h2g = 1/2v2² + 1/2v1²
multiply both side by 2 and take g out from the left equation
2g(h1 - h2) = v2² + v1² where v1 is approximately 0 assuming the surface of the tank is large
v2² = 2g(h1 - h2)
take square root of both sides
v2 = √2g(h1 - h2)
h1 = 3.75 + 6.5 = 10.25
h2 = 6.5
v2 = √2g(h1 - h2) = √ (2×9.81× (10.25 - 6.5)) = 8.6 m/s
Volume in m³/s = A × v where A is the area of the hole and the radius of the hole = 2.22 mm / 2 (where 2.22 mm is the diameter of the hole) = 1.11 mm and 1.11mm / 1000 to convert it to meters
Area of the hole ( assuming it is a circle) = πr² = 3.142× (1.11/1000)²
Area = 0.00000387 m²
Volume in M³/s = 0.00000387 × 8.6 = 0.0000333 m³/s
Answer:
W = 588 N
Explanation:
The given question is ,"calculate the weight of a table on the earth whose mass is 60 kg"
The mass of the table, m = 60 kg
We need to find the weight of a table on the earth.
The weight of an object is given by :
W = mg
Where
g is acceleration due to gravity
W = 60 kg × 9.8 m/s²
W = 588 N
Hence, the weight of the table is 588 N.
Answer:
Explanation:
If no Energy is lost ( either as Sound energy or any other energy) the total energy of ball A equals the total energy of ball B
Therefore the Kinetic Energy of Ball B equals the Total Energy of Ball A minus the Potential Energy of Ball A
K. E = T. E - P.E
Answer:
352,088.37888Joules
Explanation:
Complete question;
A hiker of mass 53 kg is going to climb a mountain with elevation 2,574 ft.
A) If the hiker starts climbing at an elevation of 350 ft., what will their change in gravitational potential energy be, in joules, once they reach the top? (Assume the zero of gravitational potential is at sea level)
Chane in potential energy is expressed as;
ΔGPH = mgΔH
m is the mass of the hiker
g is the acceleration due to gravity;
ΔH is the change in height
Given
m = 53kg
g = 9.8m/s²
ΔH = 2574-350 = 2224ft
since 1ft = 0.3048m
2224ft = (2224*0.3048)m = 677.8752m
Required
Gravitational potential energy
Substitute the values into the formula;
ΔGPH = mgΔH
ΔGPH = 53(9.8)(677.8752)
ΔGPH = 352,088.37888Joules
Hence the gravitational potential energy is 352,088.37888Joules
Answer:
It has less mass than the car
Explanation:
Both car and bug have the same amount of force acting on them. As the bug mass is much smaller, it sees a greater acceleration
F = ma
