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suter [353]
3 years ago
10

Ball A is allowed to fall and strike ball B. Assume that all of ball A's energy is transferred to ball B at point I, and that th

ere is no loss of energy to other sources. Determine the kinetic energy of ball B at point II.
Physics
2 answers:
Alika [10]3 years ago
5 0

Answer:

Explanation:

If no Energy is lost ( either as Sound energy or any other energy) the total energy of ball A equals the total energy of ball B

Therefore the Kinetic Energy of Ball B equals the Total Energy of Ball A minus the Potential Energy of Ball A

K. E = T. E - P.E

otez555 [7]3 years ago
5 0

Answer:

Incomplete question:

mA = 4 kg

h point I = 5 m

mB = 2 kg

h point II = 2 m

Answer: the kinetic energy of ball B at point II is 156.8 J

Explanation:

the solution is in the attached Word file

Download docx
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Explain why the elements of the same group exhibit the same chemical behavior​
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Answer:

All the elements of a period have similar chemical properties because they have the same number of valence electrons in their outermost shell. Their atoms have the same number of electrons in the highest occupied energy level

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Chemistry Sem 2
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2 years ago
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Svetllana [295]

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Explanation:

7 0
3 years ago
A man goes for a walk, starting from the origin of an xyz coordinate system, with the xy plane horizontal and the x axis eastwar
tekilochka [14]
<h2>a) Displacement of penny = 1300 i + 2400 j - 640 k</h2><h2>b) Magnitude of his displacement = 2729.47 m</h2>

Explanation:

a) He walks 1300 m east, 2400 m north, and then drops the penny from a cliff 640 m high.

1300 m east = 1300 i

2400 m north = 2400 j

Drops the penny from a cliff 640 m high = -640 k

Displacement of penny = 1300 i + 2400 j - 640 k

b) Displacement of man for return trip = -1300 i - 2400 j

    \texttt{Magnitude = }\sqrt{(-1300)^2+(-2400)^2}=2729.47m

    Magnitude of his displacement = 2729.47 m

3 0
3 years ago
Read 2 more answers
A rock is thrown downward from an unknown height above the ground with an initial speed of 6.1 m/s. It strikes the ground 1.7 s
insens350 [35]

Answer:

24.531 m

Explanation:

t = Time taken = 1.7 s

u = Initial velocity = 6.1 m/s

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=6.1\times 1.7+\dfrac{1}{2}\times 9.8\times 1.7^2\\\Rightarrow s=24.531\ m

The initial height of the rock above the ground is 24.531 m

7 0
3 years ago
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