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suter [353]
3 years ago
10

Ball A is allowed to fall and strike ball B. Assume that all of ball A's energy is transferred to ball B at point I, and that th

ere is no loss of energy to other sources. Determine the kinetic energy of ball B at point II.
Physics
2 answers:
Alika [10]3 years ago
5 0

Answer:

Explanation:

If no Energy is lost ( either as Sound energy or any other energy) the total energy of ball A equals the total energy of ball B

Therefore the Kinetic Energy of Ball B equals the Total Energy of Ball A minus the Potential Energy of Ball A

K. E = T. E - P.E

otez555 [7]3 years ago
5 0

Answer:

Incomplete question:

mA = 4 kg

h point I = 5 m

mB = 2 kg

h point II = 2 m

Answer: the kinetic energy of ball B at point II is 156.8 J

Explanation:

the solution is in the attached Word file

Download docx
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Two radio antennas are 120 m apart on a north-south line, and they radiate in phase at a frequency of 3.4 MHz. All radio measure
chubhunter [2.5K]

Answer:

the smallest angle from the antennas is <em>47.3°</em>

Explanation:

We first need to write the expression for the relation between the wavelength (λ) and the frequency (f) of the wave, and then solve for the wavelength.

Therefore, the relation is:

λ = c /f

where

  • c is the speed of light constant
  • λ is the wavelength
  • f is the frequency

Thus,

λ = (3 × 10⁸ m/s) / (3.4 MHz)

  = (3 × 10⁸ m/s) / (3.4 MHz)(10⁶ Hz/1 MHz)

  = 88.235 m

Therefore, the smallest angle measured (from the north of east) from the antennas for the constructive interference of the two-radio wave can be calculated as

θ = sin⁻¹(λ / d)

where

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Thus,

θ = sin⁻¹(88.235 / 120)

<em>θ = 47.3 °</em>

<em></em>

Therefore, the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs is <em>47.3 °</em>.

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