Answer:
C = n + 2
Step-by-step explanation:
Well looking at the line on the graph we can see that the y intercept is 2 because the y intercept is the point in the line that touches the y axis.
And the slope is how fat away each points are from each other on a line so we can find the slope by using two points on the line, we can use (1,3) and (2,4).
So we set up the formula like this
.
And now we gotta plug in the numbers and solve so the answer is 4-3 = 1 and 2-1 = 1 so the slope is 1.
And we can’t write that as just n.
So the answer is C = n + 2.
For proof look at the image below.
Answer:
18 hours
Step-by-step explanation:
Answer:
The equation of line with given slope that include given points is 3 y + x - 20 = 0
Step-by-step explanation:
According to Cora , if we know the slope and points on a line then we can write the equation of a line .
Since , The equation of line in slope-intercept form is
y = m x + c
<u>Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .</u>
So , From the statement said above it is clear that she is correct .
Now , Again
Given as :
Slope of a line is m = - 
That include points ( 2 , 6 )
Now from the equation of line as y = m x + c
∴ 6 = -
( 2 ) + c
Or, 6 = -
+ c
So , c = 6 +
or, c =
∴ c =
So, The equation of line can be written as
y = -
x +
Or, 3 y = - x + 20
I.e 3 y + x - 20 = 0
Hence The equation of line with given slope that include given points is 3 y + x - 20 = 0 Answer
Im not really sure so ill just give it a try.
mayeb 70? ten less"
Answer: Correct answer is C -I just took the test
we have the function f(x) = 4(1/2)x, and we want to reflex it over the x-axis.
you can see in the graph that the reflex over this axis changes the sign of f(x) in all the points (where f(0) = 4, g(0) = -4, f(1) = 2, g(1) = -2, and so on), then the reflex, g(x) is equal to -f(x)
now we have:
g(x) = -f(x) = - 4(1/2)x
then the right answer is the third option:
g(x) = -4(1/2)x
Step-by-step explanation: