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omeli [17]
3 years ago
9

Pls anserw I need help

Mathematics
1 answer:
larisa [96]3 years ago
6 0

Answer:

2.7

Step-by-step explanation:

0.5+1.2+1= 2.7

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Which of the following is an example of overdraft protection?
maxonik [38]

Answer:

(B)  an update from the bank when an account balance is less than $50

Step-by-step explanation:

overdraft occurs when money is withdrawn in excess of what is on the current account. In this situation the account is said to be "overdrawn". This applies to debit cards and how much you have on your balance :)

3 0
2 years ago
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Assume that adults have IQ scores that are normally distributed with a mean of 96 and a standard deviation of 15.7. Find the pro
astraxan [27]

Answer:

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 96, \sigma = 15.7

Probability that a randomly selected adult has an IQ greater than 123.4.

This is 1 subtracted by the pvalue of Z when X = 123.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{123.4 - 96}{15.7}

Z = 1.745

Z = 1.745 has a pvalue of 0.9595

1 - 0.9595 = 0.0405

4.05% probability that a randomly selected adult has an IQ greater than 123.4.

7 0
3 years ago
What are the solution(s) to the quadratic equation 50 – x2 = 0?
timofeeve [1]

Answer:

No real solution

Step-by-step explanation:

Work is on another question for this. You have asked it multiple times

8 0
3 years ago
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Ty and Gajge are both football players who averaged 4 yards per run in yesterday’s
Anettt [7]

Answer:

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.

Step-by-step explanation:

given that Ty and Gajge are football players.

Carries is 15 for both and average is the same 4 for both.

But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.

Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)

But for Gajge, highest is 19 and lowest is 2.

i.e. range = 19-2 =17 very much higher than that of Ty

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.

5 0
3 years ago
What's greater 5/6 or7/9
Vesna [10]

Answer:

5/6 is greater

Step-by-step explanation:

First obtain a common denominator for the fractions. Multiply the denominator of one fraction to the denominator of another and that is the denominator for the new fractions (54). Then multiply the denominator of one fraction to the numerator of the other one to obtain the new numerator. (e.g. 5*9=45 so 5/6 ->45/54) do this to the other fraction and you will see that 7/9 -> 42/54 and 45/54 is greater than 42/54 so 5/6 is greater .

8 0
3 years ago
Read 2 more answers
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