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2 years ago

From first principle find the derivative of logx

Mathematics

1 answer:

Archy [21]2 years ago

4 0

Hello!

$\large\boxed{\frac{dy}{dx}logx = \frac{1}{xln10} }$

Recall that:

$logx$ can be rewritten as:

$log_{10}x$

Use the equation for the derivative of a log expression:

$\frac{dy}{dx}log_{a}u = \frac{1}{ulna} * u'$

Substitute in the values in the expression:

$logx = \frac{1}{xln10} * 1 = \frac{1}{xln10}$

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A company needs to make at least A company needs to make at least 75,000 bottles 20-oz bottles can made from 1 pound if plastic

strojnjashka [21]

Answer:

By using the recycled plastic the company will save $1050.

Step-by-step explanation:

A company needs to make at least 75,000 bottles.

Now, 20-oz bottles can be made from 1 pound.

Then, 75000-oz bottles can be made from $\frac{75000}{20} = 3750$ pounds of plastic.

Now, the cost of new plastic is $0.83 per pound.

So, cost of new plastic to make 75000 bottles will be $(3750 × 0.83) = $3112.5.

Again, the cost of recycled plastic is $0.55 per pound.

So, cost of recycled plastic to make 75000 bottles will be $(3750 × 0.55) = $2062.5.

Therefore, by using the recycled plastic the company will save $(3112.5 - 2062.5) = $1050. (Answer)

3 0

3 years ago

3(x+2)=-5-2(x-3)<br>helps plzs!!!!!.....<br>

konstantin123 [22]

3x+6=-5-2x-6
3x=-5-2x-6-6
3x+2x=-5-6-6
5x=-17
X=-17/5
X=-3.4

7 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

Which equation best represents a trend line for the scatter plot?

kvasek [131]

Y = (-3/7)x + 4

Looking at the graph, you can see the trend line plotted. And conveniently, there are a couple of points on the trend line that are indicated. Those points being (0,4) and (7,1). The equation of a line in slope intercept form is:y = ax+b

Looking at the points available, the point (0,4) already gives us the y intercept since x is equal to 0. So our equation becomes:
y = ax + 4

Now we need to determine a which is the slope. The slope is the change in y divided by the change in x. So let's do that
(1-4)/(7-0) = -3/7

And now our equation becomes:
y = (-3/7)x + 4

And given formatting issues, the first option available is the correct one.

3 0

3 years ago

Read 2 more answers

If someone could help me figure out #7 ASAP I’d really appreciate it

IceJOKER [234]

Answer: Angle N

Explanation:

For triangle ABC, we refer to the middle angle, Angle B.

For triangle MNP, we refer to its middle angle, Angle N.

Good luck!

8 0

2 years ago

From first principle find the derivative of logx​

From first principle find the derivative of logx