Question

From first principle find the derivative of logx​

Answer 1

Hello!

$\large\boxed{\frac{dy}{dx}logx = \frac{1}{xln10} }$

Recall that:

$logx$ can be rewritten as:

$log_{10}x$

Use the equation for the derivative of a log expression:

$\frac{dy}{dx}log_{a}u = \frac{1}{ulna} * u'$

Substitute in the values in the expression:

$logx = \frac{1}{xln10} * 1 = \frac{1}{xln10}$