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lianna [129]
2 years ago
10

On a coordinate plane, solid circles appear at the following points: (negative 4, 2), (negative 2, 2), (negative 1, 4), (1, 1),

(1, 3), (2, negative 3).
Which ordered pair could be removed from the graph to create a set of ordered pairs that represents a function?
Mathematics
1 answer:
Rainbow [258]2 years ago
4 0

We need to remove either (1, 4) or (1, 1) to create a function.

<h3>How to alter a relation in order to obtain a function</h3>

Relations are formed by two sets, an input set known as domain and an output set known as range and relationships between these sets. A relation is a function if and only if each element from domain is related to only one element of the range. Mathematically speaking, we must satisfy the following proposition:

x → f(x), x → f'(x) ⇒ f(x) = f'(x)

Based on this definition, there are two possibilities to create a function:

  1. Remove (1, 4)
  2. Remove (1, 1)

To learn more on functions: brainly.com/question/12431044

#SPJ1

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A sphere and a cylinder have the same radius and height. The volume of the cylinder is 8 meters cubed. Yolanda found the volume
Mrrafil [7]

Answer:

Yolanda should have found the volume by multiplying 8 by four-thirds

Step-by-step explanation:

Here, we want to find Yolanda’s error.

we proceed as follows;

Mathematically, the volume of the cylinder can be calculated using the formula;

V = pi * r^2 * h

now since the radius of the cylinder and the height is equal, we can say that h = r

and thus, the volume can be written as

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Mathematically, the volume of a sphere can be calculated using the formula

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Now from the question we know that the value of pi * r^3 =8 which is the value for the volume of the cylinder.

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5 0
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Find the following expression by multiplying <br> (A+b)^3
DaniilM [7]

Given expression: (A+b)^3.

We can expand it into three factors as (A+b)(A+b)(A+b).

First we would foil (A+b)(A+b) = A^2 + Ab+Ab+ b^2

Combining like terms, we get

= A^2 +2Ab + b^2

Now, we would multiply (A^2 +2Ab + b^2) and (A+b).

=A^3 + A^2b + 2A^2b+2Ab^2 + Ab^2+ b^3

Combining like terms, we get

=A^3+3A^2b+3Ab^2+b^3

Therefore,

\left(A+b\right)^3=\quad A^3+3A^2b+3Ab^2+b^3


8 0
3 years ago
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