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3 years ago

Please Help i got a Test Tommaro Thank u!

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

We know that - Area of a Rectangle is given by : Length × Width

Here : Length = u and Width = 26.2 ft

Given : Area of the Rectangle = 1037.52 ft²

$:\implies$ u × 26.2 = 1037.52

$\mathsf{\implies u = \dfrac{1037.52}{26.2}}$

$:\implies$ u = 39.6 ft

pentagon [3]3 years ago

7 0

Answer:

The length is 39.6 feet.

Step-by-step explanation:

Since the area is lw, we make this an equation. The width is already known, it's 26.2. So make a single variable equation: 26.2w=1037.52

dividing both sides by 26.2 gives you the answer of 39.6.

Hope this helps!

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Which of the following prefixes would be best for measuring small objects like the width of a piece of paper?

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Wayne spends 1/6th of an hour walking his dog. How much time does Wayne spend walking his dog in a week? *

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Step-by-step explanation:

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2 years ago

Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Consider the

Dafna1 [17]

Answer:

a) $\bar d= \frac{\sum_{i=1}^n d_i}{n}=72.2$

$s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =9.311$

b) The 90% confidence interval would be given by (63.330;81.070)

$63.330 < \mu_{left}- \mu_{right}$

Step-by-step explanation:

1) Previous concepts and notation

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let put some notation

x=left arm , y = right arm

x: 175 169 182 146 144

y: 102 101 94 79 79

The first step is define the difference $d_i=x_i-y_i$ , that is given so we have:

d: 73, 68, 88, 67, 65

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=72.2$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =9.311$

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar d \pm t_{\alpha/2}\frac{s_d}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,4)".And we see that $t_{\alpha/2}=2.13$