The true statement is (c) Yes, the sequence is an isometry transformation because it contains only rigid transformation
<h3>How to determine the type of transformation?</h3>
The coordinates are given as:
A = (1, 2), B = (3, 2) and C = (2, 7)
D = (3, -6), E = (5, -6) and F = (4, -1)
Calculate the lengths of pre-image and the image using
d = √(x2 - x1)² + (y2 - y1)²
So, we have:
AB = √(1 - 3)² + (2 - 2)² = 2
DE = √(3 - 5)² + (-6 + 6)² = 2
AB and DE are congruent
BC = √(3 - 2)² + (2 - 7)² = √26
EF = √(5 - 4)² + (-6 + 1)² = √26
BC and EF are congruent
CA = √(2 - 1)² + (7 - 2)² = √26
FD = √(4 - 3)² + (-1 + 6)² = √26
CA and FD are congruent
Because the corresponding sides are congruent, then the transformation is an isometry transformation.
This is so because isometry transformation do not alter side lengths and angles
Hence, the true statement is (c) Yes, the sequence is an isometry transformation because it contains only rigid transformation
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