You should show a picture of the graph so we can answer it
The mass of ethanol (alcohol) = 538.016 g
<h3>Further explanation</h3>
Given
Reaction
C₁₂H₂₂O₁₁(aq)+H₂O(I) = CH₃CH₂OH(aq)+CO₂(g)
1 kg of sugar = 1000 g
Required
The mass of ethanol
Solution
Balanced equation
C₁₂H₂₂O₁₁(aq)+H₂O(I) = 4CH₃CH₂OH(aq)+4CO₂(g)
mol of sugar (MW = 12.12+22.1+11.16=342 g/mol) :
mol = mass : MW
mol = 1000 g : 342 g/mol
mol = 2.924
From the equation, mol ratio of C₁₂H₂₂O₁₁ : CH₃CH₂OH = 1 : 4, so mol ethanol =
= 4 x mol sugar
= 4 x 2.924
= 11.696
Mass of ethanol(MW=46 g/mol) :
mass = mol x MW
mass = 11.696 x 46
mass = 538.016 g
EGGBEATER KICK: <em>RESTING AND PASSING</em>
There are two phases:
a power stroke and a recovery stroke. The power stroke is the same as the underwater pull on the freestyle stroke and creates power.
Answer:
Most of the matter around us, however, consists of mixtures of pure substances. Air, wood, rocks and dirt are examples of such mixtures. Mixtures can be further classified as Homogeneous and Heterogeneous.
Answer:
123.0*12.35/(0.05*6.049)
first do in small bracket 123.0*12.35/0.30245
and then divide 123.0*40.83319557
and multiply 5022.483055