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xxMikexx [17]
3 years ago
5

mercury metal is poured into a graduated cylinder that holds exactly 22.5 mL. the mercury used to fill the cylinder weighs 306.0

g. from this information, calculate the density of mercury.
Chemistry
2 answers:
SpyIntel [72]3 years ago
4 0
306.0g/22.5mL= 13.6 mL/g
D=m/v
The mass is 306.0
The volume is 13.6
xeze [42]3 years ago
4 0

<u>Answer:</u> The density of mercury is 13.6 g/mL

<u>Explanation:</u>

To calculate the density of a substance, we use the equation:

\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}

We are given:

Mass of mercury = 306.0 g

Volume of mercury = 22.5 mL

Putting values in above equation, we get:

\text{Density of mercury}=\frac{306.0g}{22.5mL}\\\\\text{Density of mercury}=13.6g/mL

Hence, the density of mercury is 13.6 g/mL

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Zinc sulfate is a 2-ion electrolyte,
Gekata [30.6K]

<u>Answer:</u> The value of <em>i</em> is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

<u>Explanation:</u>

The equation used to calculate the Vant' Hoff factor in dissociation follows:

\alpha =\frac{i-1}{n-1}

where,

\alpha = degree of dissociation = 40% = 0.40

i = Vant' Hoff factor

n = number of ions dissociated = 2

Putting values in above equation, we get:

0.40=\frac{i-1}{2-1}\\\\0.40=i-1\\\\i=1.4

The equation used to calculate the degee of dissociation follows:

\alpha =\frac{\text{Number of particles dissociated}}{\text{Total number of particles taken}}

Total number of particles taken = 100

Degree of dissociation = 40% = 0.40

Putting values in above equation, we get:

0.40=\frac{\text{Number of particles dissociated}}{100}\\\\\text{Number of particles dissociated}=(0.40\times 100)=40

This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.

Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.

7 0
3 years ago
A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the
stiks02 [169]

Answer:

4.09×10⁻³ is the mole fraction of sucrose

Explanation:

Mole fraction = Moles of solute or solvent/ Total moles

Let's convert the mass to moles (mass / molar mass)

38.6 g / 342 g/m = 0.113 moles of sucrose

495 g / 18 g/m = 27.5 moles of water

Total moles = 0.113 m + 27.5 m = 27.0613 moles

Mole fraction of sucrose = Moles of sucrose / Total moles

0.113 m / 27.0613 moles = 4.09×10⁻³

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The pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

<h3>What is pressure?</h3>

Pressure is the force exerted by any object on another object.

Given that, a and b separate 1 liter containers and exert pressure of 2 atm and 3 atm respectively.

When both gases a and b exert together, the pressure then

2 atm + 3 atm = 5 atm.

Thus, the pressure exerted when both gases are put together in a single 1 liter container is 5 atm.

Learn more about pressure

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