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2 years ago

What approach responds to the limitations of the other legacy-measuring methods?

Physics

1 answer:

Scorpion4ik [409]2 years ago

7 0

The other-legacy measuring methods' weaknesses are addressed by the bottom-up approach.

An organizational decision-making process known as a "bottom-up approach" begins at the bottom of the hierarchy rather than the top. In actuality, this means that choices won't always be made by the CEO or department head (this is known as a top-down approach).

What distinguishes a bottom-up strategy from a top-down approach?

When choices affecting the entire organization are made, top-down management is used, whereas bottom-up management involves all teams in these types of decisions.

The bottom-up approach often focuses its analysis on specific traits and micro features of a single stock. The focus of bottom-up investment is on fundamentals that apply to individual companies or industries.

What bottom-up management has to offer:

Promoting cooperation.
Enhancing morale.
Creating new insights.
Enabling your group.

To learn more about Bottom-up approach, visit:

brainly.com/question/14346585

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Impulse equals?<br> A) momentum x velocity<br> B) momentum x time<br> C) mass x velocity

mina [271]

Answer:

Explanation:

The impulse experienced by an object is the force•time.

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3 years ago

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What form of matter is "vapor"?

elena55 [62]

Vapor is usually made with water and it would be made with gas.

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3 years ago

A jetliner can fly 4.9 hours on a full load of fuel. Without any wind it flies at a speed of 1.88 x 102 m/s. The plane is to mak

PSYCHO15rus [73]

Answer:

1371.26 Km

Explanation:

First of all, we need to find the velocity of the plane relative to the ground since the air has a velocity of 78.2 m/s due east and without any wind, it flies at a velocity of 188 m/s.

Thus, during the west trip, the velocity will be;

Vw = Vp - Va

Vp is velocity of plane while Va is velocity of air

and since distance/time = velocity ;

Time = velocity/distance and thus;

Time during this west period ;Tw = X/(Vp - Va)

Now during the east trip,

Ve = Vp + Va

And Te = X/(Vp + Va)

From the question, the plane can fly 4.9 hours on a full load of fuel. Let's convert this to seconds because velocity is in m/s

Thus, 4.9 hours = 4.9 x 60 x 60 = 17640 seconds

So, this time will be equal to the sum of that in the west and east directions.

Thus; T = Tw + Te

From above we know Tw and Te.

Let's substitute them into the equation;

T = [X/(Vp - Va)] + [X/(Vp + Va)]

T = X[(Vp + Va + Vp - Va)/((Vp)² — (Va)²)

T = X[(2Vp)/((Vp)² — (Va)²)

Making X the subject to obtain;

X = [T((Vp)² — (Va)²)]/(2Vp)

X = [17640((188)² — (78.2)²)]/(2 x 188)

X = 515595326.4/376 = 1371264.17m = 1371.26 Km

6 0

3 years ago

An object whose mass is 300 lb experiences changes in its kinetic and potential energies owing to the action of a resultant forc

aev [14]

Answer: initial speed = 151.89 ft/s

Explanation:

1) About the question:

The question is incomplete. The final missing part is: If the object's elavation increases by 100 ft and its final velocirty is 200 ft/s, what is its initial velocity, in ft/s? Let g= 32.2 ft/s^2

2) Physical principle:

Work = change in mechanical energy

3) Formulas

Kinetic energy, KE = (1/2)mv²

Potential energy, PE = mgh

Mechanical energy, ME = KE + PE

4) Conversion of units:

i) 300 lbs = 300/2.2046 kg = 136.08 kg

ii) 140 btu = 140 × 1055.06 J = 147,708.4 J

iii) g = 9.81 m/s²

iv) 100 ft = 100 × 0.3048m = 30.48 m

v) 200 ft/s = 200 × 0.3048 m/s = 60.96 m/s

5) Solution

i) change in PE:

ΔPE = mgΔh = 136.08kg × 9.81 m/s² × 30.48m = 40,689.12 J

ii) change in KE

ΔKE = work done on the object - ΔPE = 147,708.4J - 40,689.12J = 107,019.28 J

iii) initial KE

initial KE = final KE - ΔKE = (1/2)mv² - ΔKE = (1/2) (136.08kg)(60.96m/s)² = 252,844.91J - 107,019.28J = 145,825.63J

iv) initial speed

KE = (1/2)mv² ⇒ v² = 2KE / m = 2 (145,825.63J) / 136.08 kg = 2,143.23 m²/s²

v = √v² = 46.30 m/s

v) Convert to ft/s

46.30 m/s = 46.30 / 0.3048 ft/s = 151.89 ft/s

7 0

4 years ago

The apparent displacement of an object as it is viewed from two different positions is known as

rjkz [21]

This phenomenon is known as parallax. The simplest example is this: if you are sitting in the passenger seat, the gas tank needle may appear to read empty. However, if you are the driver, you will see that you are not on empty, but should get some gas.

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4 years ago