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schepotkina [342]
3 years ago
8

A star has a declination of approximately 45°. Which of these statements is correct about the star?

Physics
1 answer:
bonufazy [111]3 years ago
6 0

The star is approximately 45° above the celestial equator.  <em>(A)</em>

"Declination" on the celestial coordinate system is equivalent to latitude on the terrestrial one.

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astone is thrown upwards with an initial velocity of 25m/s at ange of 30 to the ground. work out the stones horizantal range?
Vadim26 [7]

Explanation:

R = \dfrac{v_0^2}{g}\sin{2\theta} = \dfrac{(25\:\text{m/s})^2}{9.8\:\text{m/s}^2}\sin{60°}

\:\:\:\:=55.2\:\text{m}

4 0
3 years ago
PLEASE HELP I NEED TO SUBMIT THIS BEFORE MIDNIGHT!!!!!!!!!!!!!
Aloiza [94]

The Ohio Constitution lays out a three-part government with legislative, executive, and judicial branches just like the US Constitution. But the Ohio Constitution incorporates more elements of direct democracy and has a stronger legislative branch relative to the executive. Hopes this helps!

6 0
3 years ago
Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than st
Nezavi [6.7K]

Answer:

The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

Explanation:

Given that,

Initial temperature = 0.00°C

Resistance = 75.0 Ω

Final temperature = 525°C

Resistance = 275 Ω

We need to calculate the temperature coefficient of resistivity for a linear thermistor

Using formula for a linear thermistor

R=R_{0}(1+\alpha\Delta T)

R=R_{0}+R_{0}\alpha\Delta T

\alpha=\dfrac{R-R_{0}}{R_{0}\Delta T}

Put the value into the formula

\alpha=\dfrac{275-75}{275\times(525-0)}

\alpha=1.38\times10^{-3}^{\circ}C^{-1}

Hence, The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

4 0
3 years ago
Read 2 more answers
a bubble of air of volume 1cm^3 is released by a deep sea diver at a depth where the pressure is 4.0 atmospheres. assuming its t
lys-0071 [83]

Answer:

hope this helps!

Explanation:

Volume of the air bubble, V1=1.0cm3=1.0×10−6m3

Bubble rises to height, d=40m

Temperature at a depth of 40 m, T1=12oC=285K

Temperature at the surface of the lake, T2=35oC=308K

The pressure on the surface of the lake: P2=1atm=1×1.103×105Pa 

The pressure at the depth of 40 m: P1=1atm+dρg

Where,

ρ is the density of water =103kg/m3

g is the acceleration due to gravity =9.8m/s2

∴P1=1.103×105+40×103×9.8=493300Pa

We have T1P1V1=T2P2V2

Where, V2 is the volume of the air bubble when it reaches the surface.

V2=

8 0
3 years ago
‏Explain how an electron emitted by the photoelectric effect can have kinetic energy less than threshold energy ?
xenn [34]

Answer:

the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          K = E - Ф

Explanation:

The photoelectric effect is the emission of electrons from the surface of a metal.

This was correctly explained by Einstein, in his explanation the energy of the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          E = hf

          E = K + Ф

          K = E - Ф

The energy of the photons is given by the Planck relation E = hf and according to Einstein the number of joints must be added

            E = n hf

Therefore, depending on the value of this energy, the emitted electrons can have energy from zero onwards.

4 0
3 years ago
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