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3 years ago

Without graphing ,find where each parabola crosses the x-axis.a) y=x^-2x-3

1 answer:

8 0

When the parabola crosses the x-axis the parabola "intersects" or touches the x-axis, and therefore is an x-intercept, and we can get those by simply setting y = 0 and getting "x".

$\bf y=x^2-2x-3\implies \stackrel{y}{0}=x^2-2x-3\implies 0=(x-3)(x+1)
\\\\\\
x=
\begin{cases}
3\\
-1
\end{cases}$

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3 years ago

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Which of the following represents a positive number?

Trava [24]

Answer: OPTION C

Step-by-step explanation:

A positive number must be greater than (>) 0, so lets check which fits this condition.

--------------------------------------------

7.09+(-7.28)=-0.19 NEGATIVE

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Hope this helps!! :)

Please let me know if you have any question

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3 years ago

Which equation represents the graph of y= cosx reflected across the x-axis then shifted vertically down by 2 units?

Phoenix [80]

Answer:

y = -cos(x) -2

Step-by-step explanation:

Multiplying the function value by -1 reflects it across the x-axis. Adding -2 to the function value shifts it down by two units.

reflected: y = -cos(x)

then shifted: y = -cos(x) -2

6 0

3 years ago

What two numbers multiply to 10 and add to -29 ?

Degger [83]

Xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

so
x^2+29x+10=0
a=1
b=29
c=10
x= $\frac{-29+/- \sqrt{(-29)^{2}-4(1)(10)} }{2(1)}$
x= $\frac{-29+/- \sqrt{841-40} }{2}$
x= $\frac{-29+/- \sqrt{801} }{2}$
x= $\frac{-29+/- 3\sqrt{89} }{2}$

x= $\frac{-29- 3\sqrt{89} }{2}$ or $\frac{-29+ 3\sqrt{89} }{2}$
those are the 2 numbers
aprox=-28.65 and -0.349

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3 years ago

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What is the arithmetic rule to the sequence: <br>1/3,4/3,7/3<br><br>find: f(10)

makkiz [27]

The the value of f(n)= $\frac{28}{3}$