1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nikolay [14]
2 years ago
10

A triangle is rotated 90° about the origin. Which rule describes the transformation?

Mathematics
1 answer:
Alla [95]2 years ago
4 0

Answer: The rule (x,y)=(y,-x) describes the

transformation

Step-by-step explanation:.........bc

You might be interested in
Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
2 years ago
Tara runs an amusement park ride and needs to count the people who get on the ride. At the beginning of her shift, 132 people ha
DanielleElmas [232]
Y= the number riders over time
x= hours into Tara's shift
y= 33x + 132
6 0
3 years ago
Read 2 more answers
Simplify 8 over -4 divided by -3 over 9
Dima020 [189]

Answer: .074 continuing

8 0
3 years ago
Read 2 more answers
Solve: (a + 11)9 <br><br>plz help ill give the first person brainliest i need it in 10 minutes
ser-zykov [4K]

\\ \tt\longmapsto 9(a+11)

Apply distributive law

  • a(b+c)=ab+ac

\\ \tt\longmapsto 9a+9(11)

\\ \tt\longmapsto 9a+99

8 0
2 years ago
0.34 into a percent
vivado [14]
34% is the correct answer
3 0
3 years ago
Read 2 more answers
Other questions:
  • Write the equation of the line that passes through the points (2,−8) and (1,7). Put your answer in fully reduced point-slope for
    10·1 answer
  • Solve the following system by the substitution method.<br>1/4x+2/3y=-17/4<br>3x-y=3
    14·1 answer
  • What is the area of a trapezoid ABCD with bases
    5·1 answer
  • What is 72/4 in simplest form?
    9·2 answers
  • Evaluate the integral of arctan(1/x)
    6·1 answer
  • What is the slope of the line shown in the graph? (4 points) A. 3/-2 B.1/-2 C. 3/2 D. undefined
    13·2 answers
  • Factor completely, then place the factors in the proper location on the grid.<br> x2 - 2x - 24
    8·2 answers
  • a class has a ratio of boys to girls of 3/4 each for each statement below decide whether it is the fraction of boys in the class
    13·1 answer
  • 12. Find m please help.
    8·1 answer
  • Simplify the expression.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!