1. The semi inter quartile range is 10
2. The coefficient of quartile deviation is 0.2
<h3>1. How to determine the semi inter quartile range</h3>
- Mark: 20, 30, 40, 50, 60
- Freq: 5, 12, 27, 40, 50
- Com. freq: 5, 17, 44, 84, 134
- Semi inter quartile range =?
1st quartile (Q₁) = (134 + 1) / 4 = 33.75th = 40
3rd quartile (Q₃) = 3 (134 + 1) / 4 = 3 × 33.75 = 101.25th = 60
Semi inter quartile range = (Q₃ - Q₁) / 2
Semi inter quartile range = (60 - 40) / 2
Semi inter quartile range = 10
<h3>2. How to determine the coefficient</h3>
- 1st quartile (Q₁) = 40
- 3rd quartile (Q₃) = 60
- Coefficient of quartile deviation =?
Coefficient of quartile deviation = (Q₃ - Q₁) / (Q₃ + Q₁)
Coefficient of quartile deviation = (60 - 40) / (60 + 40)
Coefficient of quartile deviation = 0.2
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Answer:
its D
Step-by-step explanation:
got it right on edge
Answer:
Truncate 534.68 in tens place is 530
Step-by-step explanation:
- The first digit in the left side after the decimal is known as tens place value.
- In 534.68 the first digit in the left side after the decimal is 4
- round off 4 in 534. into nearest value
- The value is therefore= 530