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Vinvika [58]
1 year ago
13

A gun is fired parallel to the ground. at the same instant a bullet of equal size and mass next to the muzzle is released and dr

ops to the ground. which hits the ground first and why?
Physics
1 answer:
jolli1 [7]1 year ago
3 0

Both hits the ground <u>at the same time</u> because they have <u>same vertical acceleration</u>

<u></u>

<h3>What is vertical  acceleration?</h3>

A vertical acceleration is typically one for which the direction of the vector is vertically upward, usually aligned with and opposite to the gravity vector. But this is a descriptive term, not a rigorous or technical term. A car may accelerate along a road and that would generally be assumed to be a horizontal.

The vector perpendicular to this direction, as perhaps a suspension motion over a bump, would be described as vertical even if it is not strictly vertical.

Note that acceleration is defined as the rate of change of the velocity vector. But the gravitation vector, ‘g’, generally vertically downward, is often denoted by what acceleration a mass in free fall (absent air resistance) would experience, i.e. the relationship between mass and weight.

Learn more about vertical acceleration

brainly.com/question/19528199

#SPJ4

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Usain Bolt, a Jamaican sprinter, holds the Olympic and world records for the 100-m and 200-m dash, which he
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Answer: 10.36m/s

How? Just divide 200m by 19.3 and you will get how fast he ran per m/s
6 0
2 years ago
What happens to the amount of energy present when it is moved from one form to another
Jet001 [13]
The amount of energy is ALWAYS conserved based on the law of conservation of energy. Therefore, the amount of energy will remain the same. 
3 0
3 years ago
Assume that, when we walk, in addition to a fluctuating vertical force, we exert a periodic lateral force of amplitude 25 NN at
dexar [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From the question we are told

   The amplitude of the lateral  force is  F = 25 \  N

   The frequency is   f = 1 \  Hz

   The mass of the bridge per unit length is  \mu  =  2000 \  kg /m

    The length of the central span is  d =  144 m

     The oscillation amplitude of the section  considered at the time considered is  A = 75 \ mm =  0.075 \  m

      The time taken for the undriven oscillation to decay to \frac{1}{e}  of its original value is  t = 6T

Generally the mass of the section considered is mathematically represented as

            m =  \mu  *  d

=>        m =  2000 * 144

=>        m =  288000 \ kg

Generally the oscillation amplitude of the section after a  time period  t is mathematically represented as

                 A(t) = A_o e^{-\frac{bt}{2m} }

Here b is the damping constant and the A_o is the amplitude of the section when it was undriven

So from the question  

               \frac{A_o}{e}  = A_o e^{-\frac{b6T}{2m} }

=>            \frac{1}{e}  =e^{-\frac{b6T}{2m} }

=>          e^{-1} =e^{-\frac{b6T}{2m} }

=>           -\frac{3T b}{m}  =  -1

=>         b  = \frac{m}{3T}

Generally the amplitude of the section considered is mathematically represented as

           A =  \frac{n * F }{ b *  2 \pi }

=>       A =  \frac{n * F }{ \frac{m}{3T}  *  2 \pi }

=>       n =  A  *  \frac{m}{3}  *  \frac{2\pi}{25}

=>       n = 0.075 *  \frac{288000}{3}  *  \frac{2* 3.142 }{25}

=>       n = 1810 \ people

3 0
3 years ago
Why sounds hear clearly at night than day? <br><br><br>No one give proper answer. ​
Verdich [7]

when you carry the 2 and add the 3 its Z

3 0
3 years ago
During a lie detector test, a voltage of 6V is impressed across two fingers. When a certain question is asked, the resistance be
sdas [7]

The current initially through the fingers is : 1.5 * 10⁻⁵ amp

The current when the resistance between them drops is : 3 * 10⁻⁵ amp

<u>Given data : </u>

Voltage ( V ) = 6 V

Initial resistance ( r ) = 400,000 ohms

Final resistance ( R ) = 200,000 ohms

<h3>Determine The Current </h3>

A) initially through fingers

I = V / r

 = 6 V / 400,000

 = 1.5 * 10⁻⁵ amp

B) when the resistance between them drops

I = V / R

 = 6 V / 200000

 = 3 * 10⁻⁵ amp

Hence we can conclude that The current initially through the fingers is : 1.5 * 10⁻⁵ amp and The current when the resistance between them drops is : 3 * 10⁻⁵ amp

Learn more about current calculation : brainly.com/question/25922783

6 0
2 years ago
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