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Vinvika [58]
1 year ago
13

A gun is fired parallel to the ground. at the same instant a bullet of equal size and mass next to the muzzle is released and dr

ops to the ground. which hits the ground first and why?
Physics
1 answer:
jolli1 [7]1 year ago
3 0

Both hits the ground <u>at the same time</u> because they have <u>same vertical acceleration</u>

<u></u>

<h3>What is vertical  acceleration?</h3>

A vertical acceleration is typically one for which the direction of the vector is vertically upward, usually aligned with and opposite to the gravity vector. But this is a descriptive term, not a rigorous or technical term. A car may accelerate along a road and that would generally be assumed to be a horizontal.

The vector perpendicular to this direction, as perhaps a suspension motion over a bump, would be described as vertical even if it is not strictly vertical.

Note that acceleration is defined as the rate of change of the velocity vector. But the gravitation vector, ‘g’, generally vertically downward, is often denoted by what acceleration a mass in free fall (absent air resistance) would experience, i.e. the relationship between mass and weight.

Learn more about vertical acceleration

brainly.com/question/19528199

#SPJ4

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which unit of measure would scientist use to measure the thickness of rock layer, created as a result of volcanic activity
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A scientist would use a unit of length appropriate for the magnitude of what he or she is measuring. In this case, since rock is built up very slowly, they would probably use millimetres or centimetres. In some cases they may use meters. 
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Which is colder, 0 degree C or 20 degrees F?
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20 degrees F! 0 degrees C is equivalent to 32 degrees F, so 20 degrees F is colder.
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3 years ago
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d. e. Study the given diagram and calculate the following: i. work done by load ii. work done by effort iii. M.A iv. V.R v. effi
il63 [147K]

i. The work done by the load is load x distance moved by load.

ii. The work done by effort is effort applied x distance moved by effort.

iii. The mechanical advantage of the simple machine is Load/effort.

iv. The velocity ratio of the simple machine is 2.

v. The efficiency of the machine is M.A/V.R x 100%.

<h3>Work done by the load</h3>

The work done by the load is the product of the load and the distance through which the load is moved. The magnitude is calculated as follows;

Work done by the load = load x distance moved by load

<h3>Work done by effort</h3>

The work done by the effort is the product of the effort and the distance through which the effort is applied. The magnitude is calculated as follows;

Work done by effort = effort applied x distance moved by effort

<h3>Mechanical advantage of the simple machine</h3>

M.A = Load/Effort

<h3>Velocity ratio of the simple machine</h3>

V.R = distance moved by effort / distance moved by load

V.R  = 30 cm/15 cm

V.R = 2

<h3>Efficiency of the machine</h3>

E = (M.A/V.R) x 100%

Thus, the work done by the load is load x distance moved by load.

The work done by effort is effort applied x distance moved by effort.

The mechanical advantage of the simple machine is Load/effort.

The velocity ratio of the simple machine is 2.

The efficiency of the machine is M.A/V.R x 100%.

Learn more about mechanical advantage here: brainly.com/question/25984831

#SPJ1

4 0
2 years ago
A bullet with mass m = 0.1 kg grams hits a ballistic pendulum with length L = 3 meters and mass M = 2 kg and lodges in it. When
Mnenie [13.5K]

Answer:

e)     v₁ = 29.7 m / s

Explanation:

Let's propose the solution of the problem, let's start at the moment

Initial

        p₀ = m v₁

Final

     p_{f} = (m + M) v

The moment is preserved

      p₀ =  p_{f}

      m v₁ = (m + M) v

      v = m / (m + M) v₁        (1)

a) energy is conserved

Let's look for kinetic energy

Initial

      K₀ = ½ m v₁²

Final

      K_{f} = ½ (m + M) v²

Let's replace v

     K_{f} = ½ (m + M) [m / (m + M) v₁]²

      K_{f} = ½ m² / (m + M) v₁²

Let's look for the relationship of these energies

     Ko / K_{f} = ½ m v₁² / (½ m² / (m + M) v₁²)

     Ko / K_{f}= (m + M) / m = (1 + M / m)²

The kinetic energy changes therefore it is not conserved in the process, the missing energy is converted into potential heat energy during the crash

b) The impulse is conserved because the system is defined as formed by the two bodies and the externals are of action and reaction, so for the complete system the sum is zero and the moment does not change in value

c) in this case the system is already formed by the two bodies and since there is no rubbing the mechanical energy is conserved, transforming from kinetics to potential

d) when the pendulum oscillates the speed changes from v to zero, so the moment is not conserved, this is because there is an external force acting on the system, the force of gravity

e) For this part let's start at the end of the movement

It is system (bullet + block) moves, energy is conserved

Final. Highest point

          Em_{f} = U = (m + M) g h

Initial. Lowest point

          Em₀ = K = ½ (m + M) v2

          Em₀ =  Em_{f}

          ½ (m + M) v² = (m + M) g h

          v = √ 2gh

Let's look for the height (h) by trigonometry

         Cos 15 = x / L

          h = L-x

          h = L - L cos 15

          h = L (1- cos 15)

We replace

          v = √ (2gL (1- cos 15))

Now we use equation (1) of momentum conservation

         v = m / (m + M) v1

         v₁ = (m + M) / m v

         v1 = (0.1 +2.0) /0.1 RA (2 9.8 3 (1- cos 15))

         v₁ = 21 √ (2.00)

        v₁ = 29.7 m / s

6 0
3 years ago
A coin is resting on the bottom of an empty container. The container is then filled to the brim three times, each time with a di
Virty [35]

Answer:

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

Explanation:

Let the depth of each section is h.

That means the real depth for each section is h.

Apparent depth is liquid A is 7 cm.

Apparent depth in liquid B is 6 cm.

Apparent depth in liquid C is 5 cm.

by the formula of the refractive index

n = real depth / apparent depth

where, n is the refractive index of the liquid.

For liquid A:

n_{A}=\frac{h}{7}    .... (1)

For liquid B:

n_{B}=\frac{h}{6}   ..... (2)

For liquid C:

n_{C}=\frac{h}{5}     ..... (3)

By comparing all the three equations

nc > nB > nA

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

5 0
3 years ago
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