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Hitman42 [59]
3 years ago
9

If a person pushes a box up a ramp, in which direction will the box exert a force on the person? up the ramp toward the person d

own on the ramp
Physics
2 answers:
Dmitrij [34]3 years ago
6 0
The box would go toward the person
EleoNora [17]3 years ago
4 0
Down the ramp toward the person
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A car travels 90 meters north in 15 seconds. Then turns around and travels at 40 meters south in 5.0 seconds. what is the averag
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Average velocity  =  (displacement) / (total time)

Displacement = distance and direction between
                             the starting point and the end point

The car travels 90 meters north, then 40 meters south. 
So it ends up 50 meters north of where it began. 

Displacement = 50 meters north
Total time  =  (15 + 5) = 20 seconds

Average velocity = (50 meters north) / (20 seconds)

                             =  2.5 m/s north
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Your neighbor is riding her bike around the block. When she slows down and turns a corner, what changes about her?
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Answer:

a) her velocity

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How does volcanic ash in earth's atmosphere affect solar radiation?
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What would be the orbital speed and period of a satellite in orbit 0.82 ✕ 108 m above the earth?
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A particular balloon can be stretched to a maximum surface area of 1257 cm2. The balloon is filled with 3.1 L of helium gas at a
chubhunter [2.5K]

Answer:

The ballon will brust at

<em>Pmax = 518 Torr ≈ 0.687 Atm </em>

<em />

<em />

Explanation:

Hello!

To solve this problem we are going to use the ideal gass law

PV = nRT

Where n (number of moles) and R are constants (in the present case)

Therefore, we can relate to thermodynamic states with their respective pressure, volume and temperature.

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} --- (*)

Our initial state is:

P1 = 754 torr

V1 = 3.1 L

T1 = 294 K

If we consider the final state at which the ballon will explode, then:

P2 = Pmax

V2 = Vmax

T2 = 273 K

We also know that the maximum surface area is: 1257 cm^2

If we consider a spherical ballon, we can obtain the maximum radius:

R_{max} = \sqrt{\frac{A_{max}}{4 \pi}}

Rmax = 10.001 cm

Therefore, the max volume will be:

V_{max} = \frac{4}{3} \pi R_{max}^3

Vmax = 4 190.05 cm^3 = 4.19 L

Now, from (*)

P_{max} = P_1 \frac{V_1T_2}{V_2T_1}

Therefore:

Pmax= P1 * (0.687)

That is:

Pmax = 518 Torr

6 0
3 years ago
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