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3 years ago

A car drives for 50 seconds and travels 2 meters what is its velocity

Physics

2 answers:

kupik [55]3 years ago

8 0

Answer:

speed = distance/time so v = 100/50 m/sec = 2 m/sec.

D = 2T ⇐formula for distance, in meters, for trip duration in T seconds, ASSUMING CONSTANT SPEED.

enyata [817]3 years ago

3 0

Speed = (distance) / (time)

Speed = (2 m) / (50 s)

Speed = 0.04 m/s

There's not enough information to state the car's velocity. We don't know anything about the direction it moved.

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A thin stream of water flows smoothly from a faucet and falls straight down. at one point the water is flowing at a speed of v1

kati45 [8]

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3 years ago

Answer these questions plz

lozanna [386]

1. The property of a conductor by virtue of which it posses the flow of electric current through it is called resistance.

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3 years ago

One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (cre

elixir [45]

Answer:

wavelength.

Explanation:

One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (crest) and lowest (trough) points, and returning to the same value as the starting point is called a is called wavelength. Its can be also defined as the distance between two successive crests or trough points in wave form.

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2 years ago

A steel wire of length 31.0 m and a copper wire of length 17.0 m, both with 1.00-mm diameters, are connected end to end and stre

Brut [27]

Answer:

The time taken is $t = 0.356 \ s$

Explanation:

From the question we are told that

The length of steel the wire is $l_1 = 31.0 \ m$

The length of the copper wire is $l_2 = 17.0 \ m$

The diameter of the wire is $d = 1.00 \ m = 1.0 *10^{-3} \ m$

The tension is $T = 122 \ N$

The time taken by the transverse wave to travel the length of the two wire is mathematically represented as

$t = t_s + t_c$

Where $t_s$ is the time taken to transverse the steel wire which is mathematically represented as

$t_s = l_1 * [ \sqrt{ \frac{\rho * \pi * d^2 }{ 4 * T} } ]$

here $\rho_s$ is the density of steel with a value $\rho_s = 8920 \ kg/m^3$

$t_s = 31 * [ \sqrt{ \frac{8920 * 3.142* (1*10^{-3})^2 }{ 4 * 122} } ]$

$t_s = 0.235 \ s$

And

$t_c$ is the time taken to transverse the copper wire which is mathematically represented as

$t_c = l_2 * [ \sqrt{ \frac{\rho_c * \pi * d^2 }{ 4 * T} } ]$

here $\rho_c$ is the density of steel with a value $\rho_s = 7860 \ kg/m^3$

$t_c = 17 * [ \sqrt{ \frac{7860 * 3.142* (1*10^{-3})^2 }{ 4 * 122} } ]$

$t_c =0.121$

$t = t_c + t_s$

$t = 0.121 + 0.235$

$t = 0.356 \ s$

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3 years ago

When conducting scientific research, any information that is found must be analyzed to determine its validity. John believes tha

SashulF [63]

Answer:

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Explanation:

Well...generally the above observation may seem wrong but it isn't. That's because according to scientific point of view, if he saw a real UFO flying out in the air then it is logically possible that some being of an advance civilization must be piloting that craft. If the observation is correct then it can't just be a coincidence at all.

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3 years ago

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