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1 year ago

2 a A pile of 60 sheets of paper is 6 mm high. Calculate the average thickness of a sheet of the paper.

Physics

1 answer:

fiasKO [112]1 year ago

6 0

The average thickness of a sheet of the paper is 0.1 mm.

The number of ice blocks that can be stored in the freezer is 80 blocks of ice.

<h3>Average thickness of a sheet of the paper</h3>

The average thickness of a sheet of the paper is calculated as follows;

average thickness = 6 mm/60 sheets = 0.1 mm /sheet

Thus, the average thickness of a sheet of the paper is 0.1 mm.

<h3>Volume of each block of ice</h3>

Volume = 10 cm x 10 cm x 4 cm

Volume = 400 cm³

<h3>Volume of the freezer</h3>

Volume = 40 cm x 40 cm x 20 cm = 32,000 cm³

<h3>Number of ice blocks that can be stored</h3>

n = 32,000 cm³/400 cm³

n = 80 blocks of ice

Thus, the number of ice blocks that can be stored in the freezer is 80 blocks of ice.

Learn more about average thickness here: brainly.com/question/24268651

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3 years ago

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a man uses a 900 watt electric iron to press his clothes for an average of 4 hours a week for five weeks if the cost of an elect

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Answer:

54 Kobo

Explanation:

Units of <u>electricity</u> are measured in kilowatt hours (kWh).

Given information:

900 watt electric iron
Appliance usage = 4 hours a week for 5 weeks
Unit cost of electricity = 3 Kobo per kWh

Convert the wattage of the electric iron from watts to kilowatts.

1000 watts (W) = 1 kilowatt (kW)

⇒ 900 watts = 1 ÷ 1000 = 0.9 kilowatts

This means that the power consumption of the electric iron is 0.9 kW per hour of use.

Total hours spent pressing clothes:

= 4 hours per week for 5 weeks

= 4 × 5

= 20 hours

<u>Total power consumption</u>:

= number of kW × number of hours

= 0.9 × 20

= 18 kWh

To find the <u>total cost</u>, multiply the total kWh by the cost per kWh:

⇒ Cost = 18 × 3 = 54 Kobo

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2 years ago

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A toy cart is pulled a distance of 6.00 m in a straight line across the floor. The force pulling the cart has a magnitude of 20.

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Answer:

W = 95.8J

Explanation:

Given

S = 6.00m

F =20.0N

Theta = 37°

W = FSCos(theta)

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3 years ago

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You observe that a mass suspended by a spring takes 0.25 s to make a full oscillation. What is the frequency of this oscillation

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Answer:

Frequency of oscillation, f = 4 Hz

time period, T = 0.25 s

Angular frequency, $\omega = 25.13 rad/s$

Given:

Time taken to make one oscillation, T = 0.25 s

Solution:

Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:

f = $\frac{1}{T}$

f = $\frac{1}{0.25}$

Frequency of oscillation, f = 4 Hz

The period of oscillation can be defined as the time taken by the suspended mass for completion of one oscillation.

Therefore, time period, T = 0.25 s

Angular frequency of oscillation is given by:

$\omega = 2\pi \times f$

$\omega = 2\pi \times 4$

$\omega = 25.13 rad/s$

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3 years ago

At 15°C air is transmitted <br>at 340 m/s. Express this speed<br>in Kilometers per hour.

EleoNora [17]

Answer:

1224km/hr

Explanation:

To convert from m/s to km/hr

1000m = 1km

Divide both sides by 1000

1m = 1/1000 km................. (1)

60×60 seconds = 1 hr

3600s = 1hr

Divide both sides by 3600

1s = 1/3600 .............(2)

Divide (2) by (1)

1m/s = 1/1000 ÷ 1/3600 km/hr

1m/s = 1/1000 × 3600/1 km/hr

1m/s = 3600/1000 km/hr

1m/s = 3.6 km/hr .............(3)

To convert 340m/s to km/hr

Multiply (3) by 340

1× 340m/s = 3.6 × 340 km/hr

340m/s = 1224km/hr

I hope this was helpful, please mark as brainliest

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3 years ago

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