The best represent the size of visible light will be C. Protozoa
The electromagnetic spectrum, gives the overall distribution of electromagnetic radiation by the frequency or wavelength. All EM waves travel at the speed of light in a vacuum, but over a wide range of frequencies, wavelengths, and photon energies.
Visible light wavelengths cover the range of approximately 0.4 to 0.7 μm. electromagnetic spectrum that the human eye can see is the Visible light. Visible light is a form of electromagnetic (EM) radiation, along with radio waves, infrared, ultraviolet, X-rays, and microwaves. the wavelengths that are visible to most human eyes is generally known as Visible light
the best represent the size of visible light is Protozoa, According to the diagram of the electromagnetic spectrum shown,
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Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.
Answer:
= 1.7 cm
Explanation:
The magnification of the compound microscope is given by the product of the magnification of each lens
M = M₀
M = - L/f₀ 25/![f_{e}](https://tex.z-dn.net/?f=f_%7Be%7D)
Where f₀ and
are the focal lengths of the lens and eyepiece, respectively, all values in centimeters
In this exercise they give us the magnification (M = 400X), the focal length of the lens (f₀ = 0.6 cm), the distance of the tube (L = 16 cm), let's look for the focal length of the eyepiece (
)
= - L / f₀ 25 / M
Let's calculate
= - 16 / 0.6 25 / (-400)
= 1.67 cm
The minus sign in the magnification is because the image is inverted.
= 1.7 cm
If the distance between two charges is halved, the electrical force between them increases by a factor 4.
In fact, the magnitude of the electric force between two charges is given by:
![F= k \frac{q_1 q_2}{r^2}](https://tex.z-dn.net/?f=F%3D%20k%20%5Cfrac%7Bq_1%20q_2%7D%7Br%5E2%7D%20)
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
![r'= \frac{r}{2}](https://tex.z-dn.net/?f=r%27%3D%20%5Cfrac%7Br%7D%7B2%7D%20)
the magnitude of the force changes as follows:
![F'=k \frac{q_1 q_2}{r'^2}=k \frac{q_1 q_2}{( \frac{r}{2})^2 }=k \frac{q_1 q_2}{ \frac{r^2}{4} } =4k \frac{q_1 q_2}{r^2}=4 F](https://tex.z-dn.net/?f=F%27%3Dk%20%5Cfrac%7Bq_1%20q_2%7D%7Br%27%5E2%7D%3Dk%20%5Cfrac%7Bq_1%20q_2%7D%7B%28%20%5Cfrac%7Br%7D%7B2%7D%29%5E2%20%7D%3Dk%20%5Cfrac%7Bq_1%20q_2%7D%7B%20%5Cfrac%7Br%5E2%7D%7B4%7D%20%7D%20%3D4k%20%20%5Cfrac%7Bq_1%20q_2%7D%7Br%5E2%7D%3D4%20F%20%20%20)
so, the force increases by a factor 4.