Answer:
Magnesium atomic no. = 24,25,26. These are the two elements which have same atomic no
Explanation:
Answer:8.3m/sec 30 sec,
Explanation:
A student practicing for a track meet, ran 250 m in 30 sec. a. What was her average speed? 250 m = 8.3 m/sec 30 sec.
An example would be 2 types of motion. It could be rectilinear or projectile motion. There are various equations for each type. Since you don't want me to tell you the answer, I could just express it in words. Then, it will be up to you to translate into mathematical equations.
For rectilinear motion, the distance traveled is equal to the initial velocity times the time, plus one-half of the acceleration times the square of the time. For projectile motion, the maximum distance is equal to the square of the initial velocity multiplied with the square of the sine of the launch angle, all over twice the gravity.
Answer:
V1=<u>2.5ft3</u>
<u>V2=1ft3</u>
n=1.51
Explanation:
PART A:
the volume of each state is obtained by multiplying the mass by the specific volume in each state
V=volume
v=especific volume
m=mass
V=mv
state 1
V1=m.v1
V1=2lb*1.25ft3/lb=<u>2.5ft3</u>
state 2
V2=m.v2
V2=2lb*0.5ft3/lb= <u> 1ft3</u>
PART B:
since the PV ^ n is constant we can equal the equations of state 1 and state 2
P1V1^n=P2V2^n
P1/P2=(V2/V1)^n
ln(P1/P2)=n . ln (V2/V1)
n=ln(P1/P2)/ ln (V2/V1)
n=ln(15/60)/ ln (1/2.5)
n=1.51
Answer:
The magnitude of the average angular acceleration of the disk is 
.
Explanation:
Given that,
Angular velocity, 
The disk comes to rest, 
Time, t = 0.234 s
We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,
So, the magnitude of the average angular acceleration of the disk is .
