Answer:
The portfolio should invest 48.94% in equity while 51.05% in the T-bills.
Explanation:
As the complete question is not given here ,the table of data is missing which is as attached herewith.
From the maximized equation of the utility function it is evident that
![Weight=\frac{E_M-r_f}{A\sigma_M^2}](https://tex.z-dn.net/?f=Weight%3D%5Cfrac%7BE_M-r_f%7D%7BA%5Csigma_M%5E2%7D)
For the equity, here as
is percentage of the equity which is to be calculated
is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
is the risk aversion factor which is given as 4.
is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59
By substituting values.
![Weight=\frac{E_M-r_f}{A\sigma_M^2}\\Weight=\frac{8.30\%}{4(20.59\%)^2}\\Weight=0.4894 =48.94\%](https://tex.z-dn.net/?f=Weight%3D%5Cfrac%7BE_M-r_f%7D%7BA%5Csigma_M%5E2%7D%5C%5CWeight%3D%5Cfrac%7B8.30%5C%25%7D%7B4%2820.59%5C%25%29%5E2%7D%5C%5CWeight%3D0.4894%20%3D48.94%5C%25)
So the weight of equity is 48.94%.
Now the weight of T bills is given as
![Weight_{T-Bills}=1-Weight_{equity}\\Weight_{T-Bills}=1-0.4894\\Weight_{T-Bills}=0.5105=51.05\%\\](https://tex.z-dn.net/?f=Weight_%7BT-Bills%7D%3D1-Weight_%7Bequity%7D%5C%5CWeight_%7BT-Bills%7D%3D1-0.4894%5C%5CWeight_%7BT-Bills%7D%3D0.5105%3D51.05%5C%25%5C%5C)
So the weight of T-bills is 51.05%.
The portfolio should invest 48.94% in equity while 51.05% in the T-bills.
That would be false hope this helps
I think it means doing work in physics
Answer:
The answer is a TRANSLATION TOOL or D
Explanation:
Answer:
6.14 s
Explanation:
The time the rocket takes to reach the top is only determined from its vertical motion.
The initial vertical velocity of the rocket is:
![u_y = u sin \theta = (100)(sin 37^{\circ})=60.2 m/s](https://tex.z-dn.net/?f=u_y%20%3D%20u%20sin%20%5Ctheta%20%3D%20%28100%29%28sin%2037%5E%7B%5Ccirc%7D%29%3D60.2%20m%2Fs)
where
u = 100 m/s is the initial speed
is the angle of launch
Now we can apply the suvat equation for an object in free-fall:
![v_y = u_y +gt](https://tex.z-dn.net/?f=v_y%20%3D%20u_y%20%2Bgt)
where
is the vertical velocity at time t
is the acceleration of gravity
The rocket reaches the top when
![v_y =0](https://tex.z-dn.net/?f=v_y%20%3D0)
So by substituting into the equation, we find the time t at which this happens:
![t=-\frac{u_y}{g}=-\frac{60.2}{-9.8}=6.14 s](https://tex.z-dn.net/?f=t%3D-%5Cfrac%7Bu_y%7D%7Bg%7D%3D-%5Cfrac%7B60.2%7D%7B-9.8%7D%3D6.14%20s)