Answer:
The time needed is 
Explanation:
From the question we are told that
The magnitude of the stimulated acceleration due gravity is 
The diameter of the spaceship is 
Generally the force acting on the spaceship is

Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so

Thus

=> 
Generally the speed of this spaceship is mathematically represented as

=> ![v^2 = [\frac{2\pi}{T}] ^2](https://tex.z-dn.net/?f=v%5E2%20%20%3D%20%20%20%5B%5Cfrac%7B2%5Cpi%7D%7BT%7D%5D%20%5E2)
=> 
=> 
=> 
substituting values


Given that
Velocity of missile (v) = 20 m/s ,
Angle of missile (Θ) = 53°
Determine , Vertical component = v sin Θ
= 20 sin 53°
= 15.97 m/s
None of the above. 1 mL= 1 cubic centimeter
mm is the smallest.
1/16........................................
Weight equals mass times gravitational acceleration=400N, so mass=400/9.8=41kg approx.