Answer:
The inverse will be:
Step-by-step explanation:
In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :
Now solve for y'.
First add 4 in both sides of the equation and change to the left y'.
= x + 4
Second divide by 9
/9 = (x + 4)/9
= (x + 4)/9
Now you will have to clear y, with the square root.
![[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}](https://tex.z-dn.net/?f=%5Btex%5Dy%27%5E%7B%5Cfrac%7B2%7D%7B2%7D%7D%20%3D%20%5Csqrt%7Bx%20%2B%204%7D%20%20%2F%20%5Csqrt%7B9%7D)
[/tex] =
Simplifying terms
You can check the answer by doing the evaluation of the following equation:
(f o 
) (x)
substitute the equation for y' or inverse function
f(
)
Now substitue the value into f(x)
You will have
=x
(2,-3) because the 3 becomes a negative when transforming.
You need to use a common denominator. The least common denominator of 11 and 22 is 22.
3/22 + -1/11 = 3/22 + -2/22 = 3/22 - 2/22 = 1/22
Answer:
Step-by-step explanation:
The question presumes you have access to a computer algebra system. The one I have access to provided the output in the attachment. The list at the bottom is the list of the first four derivatives of f(x).
__
The derivatives alternate signs, so (-1)^k will be a factor.
The numerators start at 17 and increase by increasing factors: 2, 3, 4, indicating k! will be a factor.
The denominators have a degree that is k+1.
Putting these observations together, we can write an expression for the k-th derivative of f(x):
