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1 year ago

If n and k are positive integers and 8n = 2k , what is

Mathematics

1 answer:

ziro4ka [17]1 year ago

6 0

Answer: 1/4

Step-by-step explanation:

$8n=2k\\\\4n=k\\\\4=\frac{k}{n}\\\\\frac{n}{k}=\frac{1}{4}$

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3 years ago

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Zolol [24]

Step 1: 198 × $\frac{1}{3}$ = 66, the number of men who left the party

Step 2: 256× $\frac{1}{4}$ = 64, the number of women who left the party

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Since 130 is the number of people that left, you would subtract it from the total number of people at the party originally.

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4 years ago

A furniture store is having a sale on sofas and you're going to buy one. The advertisers know that buyers get to the store and t

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3 years ago

Define a new random variable by y = 2px. show that, as p l 0, the mgf of y converges to that of a chi squared random variable wi

Mandarinka [93]

The moment generating function (mgf) of y is given by

$M_y(t)=E(e^{ty})=E(e^{2pxt})=M_x(2pt)=p(1-e^{2pt}(1-p))^{-1}$

Since the momoent generating function of x is given by $M_x(t)=p(1-e^{t}(1-p))^{-1}$

When p tends to 0, we have

$\lim_{p \to 0} M_y(t)= \lim_{p \to 0} \frac{p}{1-e^{2pt}(1-p)} = \frac{0}{0}$

Applying L'Hopital's rule we have:

$\lim_{p \to 0} M_y(t)=\lim_{p \to 0} \frac{1}{e^{2pt}+2te^{2pt}+2pte^{2pt}} = \frac{1}{1+2t} , \ \ \ t\ \textless \ \frac{1}{2}$

This shows that y converges to <span>a chi squared random variable with 2r degrees of freedom</span>.

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3 years ago

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3 years ago

If n and k are positive integers and 8*n = 2*k , what is

If n and k are positive integers and 8n = 2k , what is