We have a square garden of 400 square foot.
The area of a square is:

where x: side length.
In this case:
![\begin{gathered} A=400=x^2 \\ x=\sqrt[]{400}=20\text{ ft} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D400%3Dx%5E2%20%5C%5C%20x%3D%5Csqrt%5B%5D%7B400%7D%3D20%5Ctext%7B%20ft%7D%20%5Cend%7Bgathered%7D)
The perimeter of the square is the sum of the lengths of the sides of the square. As they are all equal, we can write:

The fencing is priced at $1.50 per foot. If we add the 7% sales tax to this price we get:

The fencing will be installed in all the perimeter (80 ft).
We can calculate the total cost by multiplying the sales price ($1.605 per foot) and the perimeter (80 ft):

Answer: the fencing will cost a total of $128.40
Answer:
-7
Step-by-step explanation:
Domain is all real numbers.
Range is all real numbers geater than 0
Answer:
C. 
Step-by-step explanation:
To find the value f b, we need to compare the exponents.
The given exponential equation is:

Recall and apply the following rule of exponents.

We apply this rule on both sides to get:

Simplify the exponents on the left.

Comparing exponents of the same variables on both sides,


Divide both sides by 6.


Answer:
Part a) The quadratic function is 
Part b) The value of x is
Part c) The photo and frame together are
wide
Step-by-step explanation:
Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame
Let
x----> the distance from the edge of the photo to the edge of the frame
we know that

Part b) What is the value of x?
Solve the quadratic equation 
The formula to solve a quadratic equation of the form
is equal to
in this problem
we have

so
substitute in the formula

-----> the solution
Part c) How wide are the photo and frame together?
