Question

Using PT in the Coordinate System

Answer 1

Answer:

$d = \sqrt{40}$

Explanation:

Distance between two points is given by the formula,

$d= \sqrt{((x_2 - x_1)^{2} + (y_2 - y_1)^{2} )}$

Let,

$\sf Point \: 1 = (x_1,y_1)= (-3,2)$

$\sf Point \: 2 = (x_2,y_2)= (3,0)$

Substituting the given coordinate in above formula,

$d= \sqrt{((3 - ( - 3))^{2} + (0 - 2)^{2} )}$

$d = \sqrt{ {6}^{2} + ({ - 2})^{2} }$

$d = \sqrt{36 + 4}$

$d = \sqrt{40}$

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