The standard reduction potentials from the aleks data is 2540 KJ.
6Br - 2Mno₄ - 4H₂O
MnO2(s) + 4OH-(aq) + 3e- -----> MnO4-(aq) + 2H2O(l), ∆E1= -0.595 V
Br2(l) + 2e- ----> 2Br-(aq) , ∆E2= 1.066
An oxidation-discount response is a form of chemical reaction that involves a switch of electrons among species. An oxidation-reduction response is any chemical reaction in which the oxidation variety of a molecule, atom, or ion adjustments by means of gaining or dropping an electron.
Oxidation–discount reactions, normally called redox reactions, are reactions that contain the transfer of electrons from one species to every other. The species that loses electrons is stated to be oxidized, while the species that gains electrons is stated to be reduced.
Oxidation is the loss of electrons during a response by a molecule, atom, or ion. Oxidation takes place whilst the oxidation state of a molecule, atom, or ion is accelerated. the opposite process is referred to as reduction.
Now we know that ∆G= -nEF
Here, n is the number of electrons and F= 96458 Columb
So for the first half-reaction, we have 2∆E1 and n=6 hence,
∆G1= -6 × 96458 × (-1.19)= 688,710.12 J = 688.71 KJ
Similarly for the second half reaction, we have 3∆E2 and n= 6 hence,
∆G2= -6 × 96458 × (3.198) = -1,850,836.1 J = - 1850.836 KJ
i.e. ∆G = ∆G1+ ∆G2 = 688.71 + 1850.84= 2,539.55 KJ
So, ∆G( 3 significant figures)= 2540 KJ
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