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ElenaW [278]
3 years ago
9

What would be the formula for an alkane which contains 30 hydrogen atoms? C__H30 16 18 14 15

Chemistry
2 answers:
Sladkaya [172]3 years ago
6 0
The formula would be C14H30.
kirill115 [55]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

A hydrocarbon that contains only carbon and hydrogen atoms attached through single bonds is known as an alkane.

General formula for alkanes is C_{n}H_{2n+2} where n is any integer.

For example, a hydrocarbon with 30 hydrogen atoms will have the value of "n" as follows.

                        Total hydrogen atoms = 2n + 2

                                         30 = 2n + 2

                                   30 - 2 = 2n

                                            n = 14

Therefore, number of carbon atoms in this hydrocarbon will be 14.

Hence, we can conclude that formula for an alkane which contains 30 hydrogen atoms is C_{14}H_{30}.

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If there is 25.0 L of gas at a temperature of 350C what is the temperature if the volume increases to 75.0L?
Zielflug [23.3K]

Answer:

The new temperature is 1596 C.

Explanation:

Charles's Law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Statistically, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Being an initial state 1 and a final state 2, it is fulfilled:

\frac{V1}{T1}=\frac{V2}{T2}

In this case:

  • V1= 25 L
  • T1= 350 C= 623 K (being 0 C= 273 K)
  • V2= 75 L
  • T2= ?

Replacing:

\frac{25 L}{623 K} =\frac{75 L}{T2}

Solving:

T2*\frac{25 L}{623 K} =75 L

T2=75 L*\frac{623 K}{25 L}

T2= 1869 K= 1596 C

<u><em>The new temperature is 1596 C.</em></u>

4 0
3 years ago
When 189.6 g of ethylene (C2H4) burns in oxygen to give carbon dioxide and water, how many grams of CO2 are formed?
BaLLatris [955]

Answer:

6.76

Explanation:

6 0
4 years ago
Consider the following multistep reaction:
chubhunter [2.5K]

The question is incomplete, here is the complete question:

Consider the following multistep reaction:

C+D⇌CD (fast)

CD+D→CD₂ (slow)

CD₂+D→CD₃ (fast)

C+3D→CD₃

Based on this mechanism, determine the rate law for the overall reaction.

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[C][D]^2

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

C+3D\rightarrow CD_3

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  C+D\rightleftharpoons CD;\text{ (fast)}

<u>Step 2:</u>  CD+D\rightarrow CD_2;\text{(slow)}

<u>Step 3:</u>  CD_2+D\rightarrow CD_3;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[CD][D]           ......(1)

As, [CD] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for CD from step 1, we get:

K=\frac{[CD]}{[C][D]}

[CD]=K[C][D]

Putting the value of [CD] in equation 1, we get:

\text{Rate}=k.K[C][D]^2\\\\\text{Rate}=k'[C][D]^2  

Hence, the rate law for the reaction is \text{Rate}=k'[C][D]^2

5 0
3 years ago
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