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ElenaW [278]
3 years ago
9

What would be the formula for an alkane which contains 30 hydrogen atoms? C__H30 16 18 14 15

Chemistry
2 answers:
Sladkaya [172]3 years ago
6 0
The formula would be C14H30.
kirill115 [55]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

A hydrocarbon that contains only carbon and hydrogen atoms attached through single bonds is known as an alkane.

General formula for alkanes is C_{n}H_{2n+2} where n is any integer.

For example, a hydrocarbon with 30 hydrogen atoms will have the value of "n" as follows.

                        Total hydrogen atoms = 2n + 2

                                         30 = 2n + 2

                                   30 - 2 = 2n

                                            n = 14

Therefore, number of carbon atoms in this hydrocarbon will be 14.

Hence, we can conclude that formula for an alkane which contains 30 hydrogen atoms is C_{14}H_{30}.

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3 years ago
How many molecules of O2 are in 153.9 g O2?
MrRissso [65]

Answer:

2.895*10^24

Explanation:

mass of Oxygen give = 153.9g

molar mass of O2 molecule = 16*2=32g/mol

n= mole

To find the mole

n= mass/ molar mass

n= 153.9/32

n=4.81mol.

To find the number of molecules of o

Nm= number of molecule

Nn = Number of mole

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Nm= Nn * NA

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3 0
3 years ago
Draw the structure of (z)-3-bromo-6-methyl-2-heptene. be sure the stereochemistry is drawn clearly.
Anna007 [38]

Explanation: In IUPAC, E-Z convention is given for describing the cis - trans notation to the isomers. According to CIP rule, the groups on the doubly bonded carbon atoms are given priorities based on the the atomic masses of first connected atom.

If the highest priority groups are on the same side, it is known as Z-form and if the highest priority groups are on opposite side, it is known as E-form.

We are given (Z)-3-bromo-6-methyl-2-heptene, in this the highest priority groups are bromine on one side and methyl- group on another side.

The structure is provided in the image below.

6 0
3 years ago
f 65mL of sulfuric acid and 25mL of sodium hydroxide were mixed and the solution had a density of 1.01g/mL, what is the heat of
user100 [1]

The question is incomplete, here is the complete question:

If 65 mL of sulfuric acid and 25 mL of sodium hydroxide were mixed and the solution had a density of 1.01 g/mL, What is the heat of the calorimeter in kJ given the temperature change of the above equation is -5.5 K. You may assume the solution has a heat capacity of 4.180 J/gK. Express your final answer in kJ and with 2 decimal places

<u>Answer:</u> The heat of the calorimeter is 2.09 kJ

<u>Explanation:</u>

To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.01 g/mL

Volume of solution = [65 + 25] mL = 90 mL

Putting values in above equation, we get:

1.01g/mL=\frac{\text{Mass of solution}}{90mL}\\\\\text{Mass of solution}=(1.01g/mL\times 90mL)=90.9g

To calculate the heat released by the reaction, we use the equation:

q=mc\Delta T

where,

q = heat released

m = mass of solution = 90.9 g

c = heat capacity of solution = 4.180 J/g.K

\Delta T = change in temperature = -5.5 K

Putting values in above equation, we get:

q=90.9g\times 4.180J/g.K\times (-5.5K)=-2089.8J=-2.09kJ

Heat released by the solution will be equal to the heat absorbed by the calorimeter.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

Heat absorbed by the calorimeter = -(-2.09) = 2.09 kJ

Hence, the heat of the calorimeter is 2.09 kJ

8 0
4 years ago
What atom has 48 neutrons,and 32 protons
Mekhanik [1.2K]
Germanium as it has 32 protons
8 0
4 years ago
Read 2 more answers
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