Answer:
correct
Explanation:
makes sense just re-write!
Answer:
40.03g/mole
Explanation:
Given parameters:
Mass = 42.10 g/mole and abundance = 93.50%
Mass = 8.30 g/mole and abundance = 6.200%
Mass = 50.40 g/mole and abundace = 0.3000%
Find;
Average atomic mass = ?
Solution:
Average atomic mass = sum (mass x abundance)
Average atomic mass = (
) + (
x 8.3) + (
)
= 39.36g/mole + 0.52g/mole + 0.15g/mole
= 40.03g/mole
Answer:
The salt is barium chloride.
Explanation:

Moles of barium sulfate =
According to reaction, 1 mol of barium sulfate is produced from 1 mol of
.
Then 0.0480 moles will be produced from:
of
.
Mass of
used = 10.00 g
Moles of
=\frac{10.00 g}{\text{Molar mass}}[/tex]

Molar mass of
= 208.33 g/mol
The nearest answer to our answer is
.
The correct answer barium chloride with molar mass of 208.2 g/mol.
Answer:
The questions are incomplete
Explanation:
(b) This question is incomplete. However to calculate the number of moles of CuSO₄ present in the impure sample. The formula below can be used;
number of moles = mass of CuSO₄ present in the impure sample ÷ molar mass of CuSO₄
(c) This question is also incomplete. However, to calculate the mass percentage of CuSO₄ present in the impure sample of CuSO₄, the formula below can be used.
Mass percentage of CuSO₄ =
mass of CuSO₄ present in the impure sample/mass of impure CuSO₄ × 100
Thus, the mass of the impure sample must be measured also since the actual mass of the CuSO₄ present in the impure sample must have been measured before calculating the number of moles.
The liquid freezes at 32 degrees celcius(A) is not the properties of water as water freezes at 0 degrees celcius