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xenn [34]
3 years ago
5

PLEASE HELP: 60 POINTS

Chemistry
2 answers:
kakasveta [241]3 years ago
8 0

Answer:

All of the above except adding a proton to the nucleus.

Explanation:

Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.  

There are two types of beta decay: beta minus and beta plus.  

In beta plus decay, a proton is converted to a neutron, positron and an electron neutrino, so mass number does not change.

In beta minus decay (atomic number Z is increased by one) neutron is converted to a proton and an electron and an electron antineutrino.

For example, nuclear reaction:

²⁶Na → ²⁶Mg + e⁻(electron) + ve(electron antineutrino

ziro4ka [17]3 years ago
6 0
The answer is “decreasing mass by one unit”
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Answer:

simple machine

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A seesaw is a simple machine, which just sways back and forth.

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A mechanical machine has many screws, and is run by a human with a remote or something else.

The answer to the question has to be simple machine. Hope this helps!

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volume is the amount of space something occupies

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What is the difference between the soluble and insoluble substances​
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Soluble means that something will "dissolve" in a substance (typically water). This means that the substance is polar (like water)

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When each of the following is heated to 50 degrees Celsius and the temperature is held constant for five minutes, which one unde
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3 years ago
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A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
Andre45 [30]

Answer:

* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

* m=2.46m

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

7 0
3 years ago
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