No of molecules=26.02×10²³molecules
No of moles
- 26.02×10²³/6.023×10²³
- 4.3mol
Molar mass
- C2H8
- 2(12)+8(1)
- 24+8
- 32g/mol
Mass
- Moles×Molar mass
- 32(4.3)
- 137.6g
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the rate constant at 55 °C by using the temperature-variable version of the Arrhenius equation:
Thus, we plug in the temperatures, activation energy and universal constant of gases in consistent units to obtain:
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D.electron
The part of the atom involved in a chemical reaction is the electron cloud. The electron cloud is the part of the atom surrounding the nucleus.
The grams of N2 that are required to produce 100.0 l of NH3 at STP
At stp 1moles = 22.4 l. what about 100.0 L of NH3
= 100 / 22.4 lx1 moles = 4.46 moles of NH3
write the reacting equation
N2+3H2 =2NH3
by use of mole ratio between N2 to NH3 which is 1:2 the moles of N2 =4.46/2 =2.23 moles of N2
mass = moles x molar mass
= 2.23moles x 28 g/mol = 62.4 grams
