Carbon has 4 electrons in its outermost shell.it shows tetravalency and catination property hence forms long chain of carbon .
Please give me brainleist. :)
Answer:
2a. If the temperature is increased, the reaction will shift to the right in an attempt to release some of the heat. As the forward reaction loses heat while the reverse would create more heat.
2b. If the pressure is increased, it would shift to the left to counteract the increase in pressure as the left side will have fewer molecules.
2c. If Cl2 is added the reaction will shift to the left in order to remove the stress of the extra Cl2 and favor the production of more reactant.
2d. If PCl3 is removed, the reaction will shift to the right. When part of the equation is removed the reaction learns to adapt to the loss by trying to make more Pcl3 and counteract the effects of losing the PCl3.
3a. The reaction will shift to the right to produce more heat and counter the negative effects of losing the heat.
3b. It will shift to the left to get rid of the excess HCl being produced and form more reactant from the breakdown of the HCl.
3c. It would shift to the right in order to get rid of the excess form products from it.
3d. If pressure is decreased there will be no effect on the shift of the reaction because there is an even amount of moles of gas on each side.
4a. K=[N2O4(g0] / [NO2(g)]2
4b. (Below)
K=[N2O4(g)] / [NO2(g)]2
0.4 / 0.5(2)
0.4/0.25 = 1.6
Keq= 1.6
Answer:
D
Explanation:
a city would first need to know the cost and benefits
Answer:
See Explanation
Explanation:
The answer should be 8 mL according to my calculations!
Answer:
1) Increase
2) Decreases
3) increases
4) Increase
Explanation:
These questions can only be answered by considering the principle which states that, "When a constraint such as a change in concentration, pressure or volume is imposed on a reaction system in equilibrium. The system will readjust itself in order to annul the constraint."
Now, if more reactants are added, the equilibrium position will shift towards the right, If more products are added, the equilibrium position will shift to the left.
Similarly, the removal of H2S causes the O2 concentration to increase since the equilibrium position now shifts to the left.
Also, addition of O2 causes H2S to be removed as the equilibrium moves to the right.
